Algebra


  1. If a = 0.1039, then the value of √4a2 − 4a + 1 + 3a is









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    a = 0.1039 (Given)
    Now,   √4a2 − 4a + 1 + 3a
    = √(1 − 2a)2 + 3a
    = 1 – 2a + 3a
    = 1 + a = 1 + 0.1039
    = 1.1039

    Correct Option: C

    a = 0.1039 (Given)
    Now,   √4a2 − 4a + 1 + 3a
    = √(1 − 2a)2 + 3a
    = 1 – 2a + 3a
    = 1 + a = 1 + 0.1039
    = 1.1039


  1. If a + b + c = 9 (where a, b, c are real numbers), then the minimum value of a2 + b2 + c2 is









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    a + b + c = 9
    a2 + b2 + c2
    = (a + b + c)2 – 2 (ab + bc + ca)
    [ab + bc + ca will be maximum if a = b = c]
    a2 + b2 + c2 = 92 – 2 × 27
    = 81 – 54 = 27

    Correct Option: C

    a + b + c = 9
    a2 + b2 + c2
    = (a + b + c)2 – 2 (ab + bc + ca)
    [ab + bc + ca will be maximum if a = b = c]
    a2 + b2 + c2 = 92 – 2 × 27
    = 81 – 54 = 27



  1. If xy + yz + zx = 0, then
    1
    +
    1
    +
    1
    (x, y, z ≠ 0) is equal to:
    x2 − yzy2 − zxz2 − xy









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    x2 − yz = x2 − + xy + zx = x (x + y + z)
    [∵  xy + yz + zx = 0
    ⇒  yz = −xy −zx]
    Similarly,
    y2 − zx = y (x + y + z)
    z2 − xy = x (x + y + z)

    ∴  Expression =
    1
    +
    1
    +
    1
    x(x + y + z)y(x + y + z)z(x + y + z)

    =
    yz + zx + xy
    = 0
    xyz(x + y + z)

    Correct Option: D

    x2 − yz = x2 − + xy + zx = x (x + y + z)
    [∵  xy + yz + zx = 0
    ⇒  yz = −xy −zx]
    Similarly,
    y2 − zx = y (x + y + z)
    z2 − xy = x (x + y + z)

    ∴  Expression =
    1
    +
    1
    +
    1
    x(x + y + z)y(x + y + z)z(x + y + z)

    =
    yz + zx + xy
    = 0
    xyz(x + y + z)


  1. If   a2 + b2 = 5ab, then the value of
    a2
    +
    b2
      is :
    b2a2









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    a2 + b2 = 5ab

    ⇒ 
    a2 + b2
    = 5
    ab

    ⇒ 
    a
    +
    b
    = 5
    ba

    On squaring both sides,
    ∴ 
    a
    +
    b
    2 = 25
    ba

    ⇒ 
    a2
    +
    b2
    + 2 = 25
    b2a2

    ⇒ 
    a2
    +
    b2
    = 25 − 2 = 23
    b2a2

    Correct Option: C

    a2 + b2 = 5ab

    ⇒ 
    a2 + b2
    = 5
    ab

    ⇒ 
    a
    +
    b
    = 5
    ba

    On squaring both sides,
    ∴ 
    a
    +
    b
    2 = 25
    ba

    ⇒ 
    a2
    +
    b2
    + 2 = 25
    b2a2

    ⇒ 
    a2
    +
    b2
    = 25 − 2 = 23
    b2a2



  1. If   x2 − 3x + 1 = 0, then the value of   x2 + x +
    1
    +
    1
      is
    xx2









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    x2 − 3x + 1 = 0
    ⇒  x2 + 1 = 3x
    Dividing both sides by x,

    ⇒  x +
    1
    = 3
    x

    ∴  x2 + x +
    1
    +
    1
    xx2

    = x2 +
    1
    + x +
    1
    x2x

    = x +
    1
    2 − 2 + x +
    1
    xx

    = 9 – 2 + 3 = 10

    Correct Option: A

    x2 − 3x + 1 = 0
    ⇒  x2 + 1 = 3x
    Dividing both sides by x,

    ⇒  x +
    1
    = 3
    x

    ∴  x2 + x +
    1
    +
    1
    xx2

    = x2 +
    1
    + x +
    1
    x2x

    = x +
    1
    2 − 2 + x +
    1
    xx

    = 9 – 2 + 3 = 10