Trigonometry


  1. If tan
    π
    -
    α
    = √3 , then the value of cosα is
    22










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    tan
    π
    -
    α
    = √3
    22

    ⇒ cot
    α
    = √3 = cot30°
    2

    α
    = cot30° ⇒ α = 60°
    2

    ∴ cosα = cos60° =
    1
    2

    Correct Option: B

    tan
    π
    -
    α
    = √3
    22

    ⇒ cot
    α
    = √3 = cot30°
    2

    α
    = cot30° ⇒ α = 60°
    2

    ∴ cosα = cos60° =
    1
    2


  1. If tan (5x – 10°) = cot (5y + 20°), then the value of (x + y) is









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    tan (90° – θ) = cotθ
    ∴ tan (5x – 10°) = cot (5y + 20°)
    ⇒ tan (5x – 10°) = tan {90° – (5y + 20°)}
    ⇒ 5x – 10° = 90° – (5y + 20°)
    ⇒ 5x – 10° = 90° – 5y – 20°
    ⇒ 5x + 5y = 70° + 10°
    ⇒ 5 (x + y) = 80°

    ⇒ x + y =
    80°
    = 16°
    5

    Correct Option: B

    tan (90° – θ) = cotθ
    ∴ tan (5x – 10°) = cot (5y + 20°)
    ⇒ tan (5x – 10°) = tan {90° – (5y + 20°)}
    ⇒ 5x – 10° = 90° – (5y + 20°)
    ⇒ 5x – 10° = 90° – 5y – 20°
    ⇒ 5x + 5y = 70° + 10°
    ⇒ 5 (x + y) = 80°

    ⇒ x + y =
    80°
    = 16°
    5



  1. If cos 20° = m and cos 70° = n, then the value of m2 + n2 is









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    cos 20° = m and cos 70° = n
    ∴ m2 + n2 = cos2 20°+ cos2 70°
    = cos2 (90° – 70°) + cos2 70°
    ⇒ sin2 70° + cos2 70° = 1

    Correct Option: A

    cos 20° = m and cos 70° = n
    ∴ m2 + n2 = cos2 20°+ cos2 70°
    = cos2 (90° – 70°) + cos2 70°
    ⇒ sin2 70° + cos2 70° = 1


  1. The value of cos 1° cos 2°cos 3° ... cos 180° is









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    ∵ cos 90° = 0
    ∴ cos1°.cos2°.... cos 180° = 0

    Correct Option: A

    ∵ cos 90° = 0
    ∴ cos1°.cos2°.... cos 180° = 0



  1. If cos 27° = x, the value of tan63° is









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    cos 27° = x
    ⇒ cos (90° – 63°) = x
    ⇒ sin 63° = x
    ∴ cos 63° = √1 - sin² 63° = √1 - x²

    ∴ tan 63 =
    sin 63°
    =
    x
    cos 63° 1 - x²

    Correct Option: A

    cos 27° = x
    ⇒ cos (90° – 63°) = x
    ⇒ sin 63° = x
    ∴ cos 63° = √1 - sin² 63° = √1 - x²

    ∴ tan 63 =
    sin 63°
    =
    x
    cos 63° 1 - x²