Trigonometry


  1. If x sin 60° tan 30° – tan²45° = cosec 60° cot 30° – sec²45°, then x =









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    x sin60° tan 30° – tan²45°
    = cosec 60°. cot30° – sec²45°

    ⇒ x .
    3
    .
    1
    - 1
    23

    =
    2
    × √3- (√2
    3

    x
    - 1 = 2 - 2 = 0
    2

    x
    = 1 ⇒ x = 2
    2

    Correct Option: A

    x sin60° tan 30° – tan²45°
    = cosec 60°. cot30° – sec²45°

    ⇒ x .
    3
    .
    1
    - 1
    23

    =
    2
    × √3- (√2
    3

    x
    - 1 = 2 - 2 = 0
    2

    x
    = 1 ⇒ x = 2
    2


  1. If x = a secα cosβ, y = b secα sinβ, z = c tan α, then the value of
    +
    -
    is









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    x = a secα . cosβ

    x
    = secα . cosβ
    α

    Similarly,
    y
    = secα . sinβ,
    z
    = tanα
    bc

    +
    -


    = sec²α. cos²β + sec²α . sin²β – tan²α
    = sec²α (cos²β + sin²β) – tan²α
    = sec²α – tan²α = 1

    Correct Option: C

    x = a secα . cosβ

    x
    = secα . cosβ
    α

    Similarly,
    y
    = secα . sinβ,
    z
    = tanα
    bc

    +
    -


    = sec²α. cos²β + sec²α . sin²β – tan²α
    = sec²α (cos²β + sin²β) – tan²α
    = sec²α – tan²α = 1



  1. If θ = 60°, then (1 / 2)√1 + sin θ + (1 / 2)√1 - sin θ is equal to









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    1
    1 + sin θ
    1
    1 1 sin θ
    22

    =
    1
    (1 + sin 60°) + √1 - sin 60°
    2


    =
    1
    (√3 + 1 + √3 - 1)
    4

    =
    2√3
    =
    3
    = cos 30°
    42

    = cos
    θ
    2

    Correct Option: D

    1
    1 + sin θ
    1
    1 1 sin θ
    22

    =
    1
    (1 + sin 60°) + √1 - sin 60°
    2


    =
    1
    (√3 + 1 + √3 - 1)
    4

    =
    2√3
    =
    3
    = cos 30°
    42

    = cos
    θ
    2


  1. The value of
    cos² 60° + 4sec² 30° - tan² 45°
    is
    sin² 30° + cos² 30°









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    Expression

    =
    cos² 60° + 4sec² 30° - tan² 45°
    sin² 30° + cos² 30°


    [∵ sin²θ + cos²θ = 1]
    =
    1
    +
    16
    - 1
    43

    =
    3 + 64 - 12
    =
    55
    123

    Correct Option: B

    Expression

    =
    cos² 60° + 4sec² 30° - tan² 45°
    sin² 30° + cos² 30°


    [∵ sin²θ + cos²θ = 1]
    =
    1
    +
    16
    - 1
    43

    =
    3 + 64 - 12
    =
    55
    123



  1. The value of sin²30° cos²45° + 5tan²30° + (3 / 2) sin²90° – 3 cos²90° is









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    sin² 30° cos² 45° + 5 tan² 30° +
    3
    sin² 90° - 3cos² 90°
    2


    3
    × 1 - 3 × 0
    2

    =
    1
    ×
    1
    + 5 ×
    1
    +
    3

    4232

    =
    1
    +
    5
    +
    3
    =
    3 + 40 + 36

    83224

    =
    79
    = 3
    7
    2424

    Correct Option: A

    sin² 30° cos² 45° + 5 tan² 30° +
    3
    sin² 90° - 3cos² 90°
    2


    3
    × 1 - 3 × 0
    2

    =
    1
    ×
    1
    + 5 ×
    1
    +
    3

    4232

    =
    1
    +
    5
    +
    3
    =
    3 + 40 + 36

    83224

    =
    79
    = 3
    7
    2424