Compound Interest
 The difference between the compound interest and the simple interest on a certain sum at 5% per annum for 2 years is Rs. 1.50. The sum is ?

 Rs. 600
 Rs. 500
 Rs. 400
 Rs. 300

View Hint View Answer Discuss In Forum
Let the sum be Rs . 100 then
S.I. = Rs.(100 x 5 x 2/100)= Rs. 10
C.I = Rs. [{100 x (1 + 5/100)^{2}}  100] = Rs. 41/4
∴ Difference between C.I and S.I = Rs. (41/4  10) = Re. 0.25
⇒ 0.25 : 150 : : 100 : P
∴ P = (1.50 x 100) / 0.25 = Rs. 600Correct Option: A
Let the sum be Rs . 100 then
S.I. = Rs.(100 x 5 x 2/100)= Rs. 10
C.I = Rs. [{100 x (1 + 5/100)^{2}}  100] = Rs. 41/4
∴ Difference between C.I and S.I = Rs. (41/4  10) = Re. 0.25
⇒ 0.25 : 150 : : 100 : P
∴ P = (1.50 x 100) / 0.25 = Rs. 600
 If the compound interest on a certain sum for 2 years at 12.5% per annum is 170, the simple interest is ?

 Rs. 150
 Rs. 152.50
 Rs. 160
 Rs. 162.50

View Hint View Answer Discuss In Forum
Let the principle is P
so compound interest = p x ( 1 + (12.5/100))sup>2  p = 170
⇒ p x (112.5/100) x (112.5/100)  p = 170
⇒ P [ 12656.25  10000 ] = 170 x 10000
∴ p = (170 x 10000) / 2656.25
Simple interest SI = (P x T x R )/100
= [{(170 x 10000) / 2656.25} x 2 x 12.5] / 100
= 160
Correct Option: C
Let the principle is P
so compound interest = p x ( 1 + (12.5/100))sup>2  p = 170
⇒ p x (112.5/100) x (112.5/100)  p = 170
⇒ P [ 12656.25  10000 ] = 170 x 10000
∴ p = (170 x 10000) / 2656.25
Simple interest SI = (P x T x R )/100
= [{(170 x 10000) / 2656.25} x 2 x 12.5] / 100
= 160
 A sum amounts to Rs. 1352 in 2 years at 4% compound interest.The sum is ?

 Rs. 1300
 Rs. 1250
 Rs. 1260
 Rs. 1200

View Hint View Answer Discuss In Forum
Let the sum be P.
Then, 1352 = P(1 +4/100)^{2}Correct Option: B
Let the sum be P.
Then, 1352 = P(1 +4/100)^{2}
⇒ 1352 = P x 26/25 x 26/25
⇒ P = (1352 x 25 x 25) / (26 x 26) = 1250
∴ Principal = Rs. 1250
 Rs. 800 at 5% per annum compound interest will amount to Rs. 882 in ?

 1 years
 2 years
 3 years
 4 years

View Hint View Answer Discuss In Forum
Let time be t years
∵ 882 = 800( 1 +5/1000)^{t}
⇒ 882/800 = (21/20)^{t}
Correct Option: B
Let time be t years
∵ 882 = 800( 1 +5/1000)^{t}
⇒ 882/800 = (21/20)^{t}
⇒ (21/20)^{2} = (21/20)^{t}
⇒ t =2
∴ Time = 2years
 The compound interest on Rs. 2800 for 1^{1}/_{2} years at 10% per annum is ?

 Rs. 441.35
 Rs. 436.75
 Rs. 434
 Rs. 420

View Hint View Answer Discuss In Forum
∵ Final Amount = Rs.[2800 x (1 + 10/100) x (1 +5/100)]
= Rs. [ 2800 x 11/10 x 21/20 ]
= Rs. 3234Correct Option: C
∵ Final Amount = Rs.[2800 x (1 + 10/100) x (1 +5/100)]
= Rs. [ 2800 x 11/10 x 21/20 ]
= Rs. 3234
∴ Required C.I. = Rs.(3234  2800) = Rs .434