Compound Interest
- A sum of money amounts to ₹ 4,840 in 2 years and to ₹ 5,324 in 3 years at compound interest compounded annually. The rate of interest per annum is :
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Let the rate of interest be r% per annum,
According to the question,4840 = P 1 + r 2 ..... (i) 100 and 5324 = P 1 + r 3 ..... (ii) 100
On dividing equation (ii) by equation (i), we have,1 + r = 5324 = 1 + 484 100 4840 4840 ⇒ r = 484 100 4840
⇒ r = 10%
Second Method to solve this question :
Here, b – a = 3 – 2 = 1 and B = Rs 5,324, A = 4,840R% = B − 1 × 100% A
Correct Option: A
Let the rate of interest be r% per annum,
According to the question,4840 = P 1 + r 2 ..... (i) 100 and 5324 = P 1 + r 3 ..... (ii) 100
On dividing equation (ii) by equation (i), we have,1 + r = 5324 = 1 + 484 100 4840 4840 ⇒ r = 484 100 4840
⇒ r = 10%
Second Method to solve this question :
Here, b – a = 3 – 2 = 1 and B = Rs 5,324, A = 4,840R% = B − 1 × 100% A R% = 5324 − 1 × 100% 4840 R% = 5324 − 4840 × 100% 4840 R% = 484 × 100% = 10% 4840
- A man borrowed some money from a private organisation at 5% simple interest per annum. He lended this money to another person at 10% compound interest per annum, and made a profit of Rs. 26,410 in 4 years. The man borrowed
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Let the principal be Rs. P.
For 4 years, S.I. = Principal × Time × Rate 100 S.I. = P × 4 × 5 = Rs. P 100 5 C.I. = P 1 + R T − 1 100 C.I. = P 1 + 10 4 − 1 100 C.I. = P 11 4 − 1 10 C.I. = P 14641 − 1 10000 C.I. = 4641P 10000
Correct Option: D
Let the principal be Rs. P.
For 4 years, S.I. = Principal × Time × Rate 100 S.I. = P × 4 × 5 = Rs. P 100 5 C.I. = P 1 + R T − 1 100 C.I. = P 1 + 10 4 − 1 100 C.I. = P 11 4 − 1 10 C.I. = P 14641 − 1 10000 C.I. = 4641P 10000
According to the question,
∴ C.I. - S.I. = 264104641P − P = 26410 10000 5 ⇒ 4641P − 2000P = 2641 10000 ⇒ 2641P = 2641 10000
⇒ P = Rs. 10000
- If the difference between the compound and simple interests on a certain sum of money for 3 years at 5% per annum is ₹ 15.25, then the sum is
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Given in question , Difference = C.I. - S.I. = ₹ 15.25 , Time = 3 years , Rate = 5%
Difference between C.I. and S.I for 3 years = PR2 300 + R (100)2 100 ⇒ 15.25 = P × 25 5 + 300 10000 100
Correct Option: A
Given in question , Difference = C.I. - S.I. = ₹ 15.25 , Time = 3 years , Rate = 5%
Difference between C.I. and S.I for 3 years = PR2 300 + R (100)2 100 ⇒ 15.25 = P × 25 5 + 300 10000 100 ⇒ 15.25 = P × 305 400 × 100 ⇒ P = 15.25 × 400 × 100 = ₹ 2000 305
- The difference between the simple and compound interest on a certain sum of money for 2 years at 4% per annum is ₹ 4. The sum is
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Here , Difference = C.I. - S.I. = ₹ 4 , Time = 2 years , Rate = 4%
Using the given formula ,Sum = Difference 100 2 r
Correct Option: A
Here , Difference = C.I. - S.I. = ₹ 4 , Time = 2 years , Rate = 4%
Using the given formula ,Sum = Difference 100 2 r Required Sum= 4 × 100 2 = ₹ 2500 4
- The difference between simple and compound interest on a certain sum of money for 2 years at 4 percent per annum is ₹ 1. The sum of money is :
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Given in question , Difference = C.I. - S.I. = ₹ 1 , , Time = 2 years , Rate = 4%
Sum = Difference × 100 2 r
Correct Option: B
Given in question , Difference = C.I. - S.I. = ₹ 1 , , Time = 2 years , Rate = 4%
Sum = Difference × 100 2 r Sum = 1 × 100 2 = ₹ 625 r