Compound Interest


  1. A sum amounts to Rs. 1352 in 2 years at 4% compound interest.The sum is ?









  1. View Hint View Answer Discuss in Forum

    Let the sum be P.
    Then, 1352 = P(1 +4/100)2

    Correct Option: B

    Let the sum be P.
    Then, 1352 = P(1 +4/100)2
    ⇒ 1352 = P x 26/25 x 26/25
    ⇒ P = (1352 x 25 x 25) / (26 x 26) = 1250
    ∴ Principal = Rs. 1250


  1. Rs. 800 at 5% per annum compound interest will amount to Rs. 882 in ?









  1. View Hint View Answer Discuss in Forum

    Let time be t years
    ∵ 882 = 800( 1 +5/1000)t
    ⇒ 882/800 = (21/20)t

    Correct Option: B

    Let time be t years
    ∵ 882 = 800( 1 +5/1000)t
    ⇒ 882/800 = (21/20)t
    ⇒ (21/20)2 = (21/20)t
    ⇒ t =2
    ∴ Time = 2years



  1. The compound interest on Rs. 2800 for 11/2 years at 10% per annum is ?









  1. View Hint View Answer Discuss in Forum

    ∵ Final Amount = Rs.[2800 x (1 + 10/100) x (1 +5/100)]
    = Rs. [ 2800 x 11/10 x 21/20 ]
    = Rs. 3234

    Correct Option: C

    ∵ Final Amount = Rs.[2800 x (1 + 10/100) x (1 +5/100)]
    = Rs. [ 2800 x 11/10 x 21/20 ]
    = Rs. 3234

    ∴ Required C.I. = Rs.(3234 - 2800) = Rs .434


  1. If Rs. 7500 are borrowed at compound interest at the rate of 4% per annum, then after 2 years the amount to be paid is ?









  1. View Hint View Answer Discuss in Forum

    Amount = Rs. 7500(1 + 4/100)2
    = Rs. 7500 x 26/25 x 26/25
    = Rs .8112

    Correct Option: D

    Amount = Rs. 7500(1 + 4/100)2
    = Rs. 7500 x 26/25 x 26/25
    = Rs .8112



  1. A sum amounts to Rs. 3149.29 in 3 years at compound interest. The sum is ?









  1. View Hint View Answer Discuss in Forum

    Let P be the principle and R% per annum be rate
    Then, P(1 +R/100)3 = 3149.28 .....(i)
    and P(1 + R/100)2 = 2916 .....(ii)

    Correct Option: C

    Let P be the principle and R% per annum be rate
    Then, P(1 +R/100)3 = 3149.28 .....(i)
    and P(1 + R/100)2 = 2916 .....(ii)
    on dividing(i) and (ii) we get
    ∴ (1 + R/100) = 3149.28/2916
    ⇒ R/100 = 233.28/2916
    ⇒ R = 233.28/2916 x 100 = 8%
    Now, P(1 + 8/100)2 = 2916
    ⇒ P x 27/25 x 27/25 = 2916
    ∴ P = (2916 x 25 x 25)/(27 x 27)
    = Rs. 2500