Let the rate be R% per annum.
Then,
1200 x (1 + R/100)² = 1348.32

Correct Option: C

Let the rate be R% per annum.
Then,
1200 x (1 + R/100)² = 1348.32
⇒ (1 + R/100)² =1348.32/1200 = 1.1236 = (1.06)²
⇒ (1 + R/100) =1.06
⇒ R/100 = 0.06
∴ R = 6%

2P = P (1 + R/100) ⁵
⇒ 2⁴ P = P(1 + R/100)²⁰
⇒ The amount becomes 2⁴ times
= 16 times and required amount = 2400 x 16 = ₹ 38400

Correct Option: B

2P = P (1 + R/100) ⁵
⇒ 2⁴ P = P(1 + R/100)²⁰
⇒ The amount becomes 2⁴ times
= 16 times and required amount = 2400 x 16 = ₹ 38400

Interest on ₹ 1440 = ₹ 216 for the third year

Correct Option: C

Interest on ₹ 1440 = ₹ 216 for the third year
⇒ Rate percentage = (216 x 100)/(1440 x 1) = 15 %

Given, P = ₹ 50000, R = 12% and n = 3 Yr
According to the formula,
Amount = P (1 + R/100 )ⁿ
= 50000 (1 + 12/100 )³

Correct Option: C

Given, P = ₹ 50000, R = 12% and n = 3 Yr
According to the formula,
Amount = P (1 + R/100 )ⁿ
= 50000 (1 + 12/100 )³
= 50000 x (28/25) x (28/25) x (28/25)
= 16 x (28 x 28 x 28)/ 5 = 351232/5
= ₹ 70246.40
∴ CI = 702446.40 - 50000 = ₹ 20246.40

Using the formula, A = p ( 1 + R/100 )ⁿ
⇒ 1352 = p(1 + 4/100 )²

Correct Option: A

Using the formula, A = p ( 1 + R/100 )ⁿ
⇒ 1352 = p(1 + 4/100 )²
⇒ 1352 = p(1.04 )²
∴ p = 1352/(1.04)² = ₹ 1250