## Speed, Time and Distance

#### Speed, Time and Distance

1. A and B are 20 km apart. A can walk at an average speed of 4 km/hr and B at 6 km/h. If they start walking towards each other at 7:000 am, when they will meet?
1. 8:00 am
2. 8:30 am
3. 9:00 am
4. 10:00 am

1. Sum of distance traveled by them after T hours
6T + 4T = 20 KM
T = 2 hours.

##### Correct Option: C

Suppose they will meet after T hours.
Distance = Speed x Time
Sum of distance traveled by them after T hours
6T + 4T = 20 km
T = 2 hours.
So they will meet at 7:00 AM + 2 hours = 9:00 AM

1. Arjun runs a distance of 1500 m in 5 minutes. What is his speed in Km/hr ?
1. 16 km/hr
2. 18 km/hr
3. 15 km/hr
4. 20 km/hr

1. Speed in Km/hr = Speed in m/sec x 18/5

##### Correct Option: B

Speed = (1500/300 ) m/sec
= 5 m/sec
= (5 x 18/5 ) km/hr
= 18 km/hr

1. In how many minutes will Rohit cover a distance of 800 m, if he runs at speed of 10 km/hr?
1. 5 min 12 sec
2. 4 min 40 sec
3. 5 min
4. 4 min 48 sec

1. Speed in m/sec = Speed in km/hr x 5/18

##### Correct Option: D

Rohit's speed = 10 Km/hr = (10 x 5/18) m/sec = 50/18 m/sec

Time taken to cover 800 m = (800 / (50/18) ) sec
= (800 x 18/50) sec = 288 sec = 4 min 48 sec

1. A plane flies along the four sides of a square field at a speed of 200, 400, 600 and 800 km/hr. Then find the average speed of plane around the square field.
1. 394
2. 400
3. 414
4. 384

1. Let the side of the square field be x and the speed of plane be y

x/200 + x/400 + x/600 + x/800 = 4x/y

##### Correct Option: D

Let the side of the square field be x and the average speed of plane be y

x/200 + x/400 + x/600 + x/800 = 4x/y
⇒ 25x/2400 = 4x/y
⇒ y =384

∴ Average speed is 384 km/hr

1. Laxman has to cover a distance of 6 km in 45 minutes . If he cover one half of the distance in 2/3rd time . what should be his speed to cover the remaining distance in the remaining time?
1. 12 km/hr.
2. 16 km/hr.
3. 3 km/hr.
4. 8 km/hr.

1. ∵ Time left = (1/3 X 45/60) hr.
= 1/4 hr.
Distance left = 3km

∴ speed required = [3 / (1/4) ] km/hr.

##### Correct Option: C

∵ Time left = (1/3 X 45/60) hr.
= 1/4 hr.
Distance left = 3km

∴ speed required = [3 / (1/4) ] km/hr.
= 3 x 4
=12km/hr .