Speed, Time and Distance


  1. For every 4 leaps taken by a dog, a cat takes 5 leaps in the same time. But distance covered in 3 leaps of dog is same as that of 4 leaps of cat. Then what is the ratio of speed of dog and cat ?
    1. 15 : 14
    2. 16 :15
    3. 12 :11
    4. 10 : 9

  1. View Hint View Answer Discuss in Forum

    Ratio of speed of dog and cat = Ratio of distance covered by them in the same time

    Correct Option: B

    Let distance covered by dog in 1 leap is x and
    Distance covered by cat in 1 leap is y

    Then, 3x = 4y
    ∴ x= 4/3y

    Now, Ratio of speed of dog and cat = Ratio of distance covered by them in the same time = 4x : 5y
    = 16/3y : 5y
    = 16 : 15


  1. Suresh traveled 1200 km by air which formed (2/5) of his trip. One-third of the whole trip he traveled by car And the rest of the journey he performed by train. The distance traveled by train was ?
    1. 1600 km.
    2. 800 km.
    3. 1800 km.
    4. 400 km.

  1. View Hint View Answer Discuss in Forum

    Let the total distance be y km.
    Then, 2y / 5 = 1200
    ⇒ y = (1200 x 5) /2 = 3000 km.

    Distance traveled by car
    = (1/3 X 3000) = 1000 km.

    Correct Option: B

    Let the total distance be y km.
    Then, 2y / 5 = 1200
    ⇒ y = (1200 x 5) /2 = 3000 km.

    Distance traveled by car
    = (1/3 X 3000) = 1000 km.

    Distance traveled by train
    = [3000- (1200 + 1000) ] km.
    = 800 km.



  1. Two cyclists A and B start from the same place at the same time. One going toward north at 18 km/hr. and other going toward south at 20 km/hr. What time will they take to be 95 km. apart ?
    1. 4 hrs. 30 min.
    2. 4 hrs. 45 min.
    3. 5 hrs.16 min.
    4. 2hrs. 30 min

  1. View Hint View Answer Discuss in Forum

    Relative velocity = u + v = 18 + 20 = 38 km
    They are 38 km. apart in 1 hr.

    Correct Option: D

    Relative velocity = u + v = 18 + 20 = 38 km
    They are 38 km. apart in 1 hr.
    ∴ They will be 95 km. apart in ( 95 / 38) hrs.
    = 2 hrs . 30 min


  1. A bullock cart has to cover a distance of 80 km. in 10 hours. If it cover half of journey in 3/5th time, what should be its speed to cover the remaining distance in time left ?
    1. 8 km/hr.
    2. 20 km/hr.
    3. 6.4 km/hr.
    4. 10 km/hr.

  1. View Hint View Answer Discuss in Forum

    Distance left = (1/2 x 80 ) km. = 40km.
    Time left - [(1-3/5) x 10 ] hrs.
    = 4 hours

    Correct Option: D

    Distance left = (1/2 x 80 ) km. = 40km.
    Time left - [(1-3/5) x 10 ] hrs.
    = 4 hours

    Required speed = (40 / 4 ) km/hr
    = 10 km/hr.



  1. The ratio between the rates of travelling of A and B is 2:3 and therefore A takes 10 min. more than the time taken by B to reach a destination, if A had walked at double the speed, he would have covered the distance in ?
    1. 30 min
    2. 25 min
    3. 15 min
    4. 20 Min

  1. View Hint View Answer Discuss in Forum

    Ratio of times taken by A and B = 1/2 : 1/3

    Suppose B takes Tb min. Then A takes (Tb + 10) min.
    ∴ (Tb + 10 ) : Tb = 1/2: 1/3
    ⇒ (Tb + 10)/Tb = 3 / 2
    ⇒ 2Tb + 20 = 3Tb
    ∴ Tb = 20


    Correct Option: C

    Ratio of times taken by A and B = 1/2 : 1/3

    Suppose B takes Tb min. Then A takes (Tb + 10) min.
    ∴ (Tb + 10 ) : Tb = 1/2: 1/3
    ⇒ (Tb + 10)/Tb = 3 / 2
    ⇒ 2Tb + 20 = 3Tb
    ∴ Tb = 20

    ∴ Time taken by A = 20 +10
    = 30 minute

    If A had walked at double speed
    Req . time = 30/2
    =15 minute