Discount


  1. The marked price of an electric iron is ₹ 690. The shopkeeper allows a discount of 10% and gains 8%. If no discount is allowed, his gain percent would be









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    Given in question , Marked price = ₹ 690
    ∴  Discount = 10%

    SP =
    690 × 90
    = ₹ 621
    100

    Profit = 8%
    ∴  CP =
    621
    × 100 = ₹ 575
    108

    Profit without discount = 690 – 575 = ₹ 115
    Profit percent =
    115
    × 100 = 20%
    575

    Using the given formula , we can find required answer :
    Here, r = 10%, R = 20%
    Required percentage =
    (r + R)
    × 100%
    100 − r

    Required percentage =
    10 + 20
    × 100%
    100 − 10

    Required percentage =
    30
    × 100%
    90

    Required percentage = 33
    1
    %
    3

    Gain = S.P. - C.P. = 480 − 400 = ₹ 80
    Gain % =
    Gain
    × 100 (without discount)
    C.P.

    =
    80
    × 100 = 20%
    400

    We can find required answer with the help of given formula :
    Here, M.P. = ₹ 690 , D = 10% , r = 8%
    M.P.
    =
    100 + r
    C.P.100 − D

    Correct Option: A

    Given in question , Marked price = ₹ 690
    ∴  Discount = 10%

    SP =
    690 × 90
    = ₹ 621
    100

    Profit = 8%
    ∴  CP =
    621
    × 100 = ₹ 575
    108

    Profit without discount = 690 – 575 = ₹ 115
    Profit percent =
    115
    × 100 = 20%
    575

    Using the given formula , we can find required answer :
    Here, r = 10%, R = 20%
    Required percentage =
    (r + R)
    × 100%
    100 − r

    Required percentage =
    10 + 20
    × 100%
    100 − 10

    Required percentage =
    30
    × 100%
    90

    Required percentage = 33
    1
    %
    3

    Gain = S.P. - C.P. = 480 − 400 = ₹ 80
    Gain % =
    Gain
    × 100 (without discount)
    C.P.

    =
    80
    × 100 = 20%
    400

    We can find required answer with the help of given formula :
    Here, M.P. = ₹ 690 , D = 10% , r = 8%
    M.P.
    =
    100 + r
    C.P.100 − D

    690
    =
    100 + 8
    C.P.100 − 10

    690
    =
    108
    C.P.90

    C.P. =
    690 × 90
    = ₹ 575
    108

    Gain % (without discount) =
    690 × 575
    × 100%
    575

    Gain % =
    115
    × 100% = 20%
    575


  1. A shopkeeper earns a profit of 10% after allowing a discount of 20% on the marked price. The cost price of the article whose marked price is ₹ 880, is









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    Given Here , marked price = ₹ 880
    SP of article = (100 – 20)% of 880 = 80% of 880
    Let CP be y
    Again, 110% of y = 704

    y =
    704
    × 100 = ₹ 640
    110

    ∴  Original cost = ₹ 640
    We can find required answer with the help of given formula :
    Here, r = 10%, D = 20%, M.P. = ₹ 880, C.P. = ?
    M.P.
    =
    100 + r
    C.P.100 − D

    Correct Option: B

    Given Here , marked price = ₹ 880
    SP of article = (100 – 20)% of 880 = 80% of 880
    Let CP be y
    Again, 110% of y = 704

    y =
    704
    × 100 = ₹ 640
    110

    ∴  Original cost = ₹ 640
    We can find required answer with the help of given formula :
    Here, r = 10%, D = 20%, M.P. = ₹ 880, C.P. = ?
    M.P.
    =
    100 + r
    C.P.100 − D

    880
    =
    100 + 10
    C.P.100 − 20

    880
    =
    110
    C.P.80

    C.P. =
    880 × 80
    110

    C.P. = ₹ 640



  1. By giving a discount of 10% on the marked price of ₹ 1100 of a cycle, a dealer gains 10%. The cost price of the cycle is :









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    Given that , discount = 10% and marked price of cycle = ₹ 1100
    Selling Price = ₹ (1100 – 10% of 1100) = ₹ (1100 – 110) = 990
    Let the cost price = y
    According to question ,
    ∴  y + 10% of y = 990

    ⇒ 
    11y
    = 990
    10

    ⇒  y =
    990 × 10
    = ₹ 900
    11

    Second method to solve this question :
    Here, r = 10% , D = 10% , M.P. = ₹ 1100 , C.P. = ?
    M.P.
    =
    100 + r
    C.P.100 − D

    Correct Option: B

    Given that , discount = 10% and marked price of cycle = ₹ 1100
    Selling Price = ₹ (1100 – 10% of 1100) = ₹ (1100 – 110) = 990
    Let the cost price = y
    According to question ,
    ∴  y + 10% of y = 990

    ⇒ 
    11y
    = 990
    10

    ⇒  y =
    990 × 10
    = ₹ 900
    11

    Second method to solve this question :
    Here, r = 10% , D = 10% , M.P. = ₹ 1100 , C.P. = ?
    M.P.
    =
    100 + r
    C.P.100 − D

    1100
    =
    100 + 10
    C.P.100 − 10

    C.P. =
    1100 × 90
    = ₹ 900
    110


  1. The marked price of an article is ₹ 200. A discount of 12
    1
    % is allowed on the marked price
    2
    and a profit of 25% is made. The cost price of the article is :









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    Given that , marked price of an article = ₹ 200

    Discount = 12
    1
    % =
    25
    %
    22

    After discount , S.P. = ₹ 200 × 87.5 = ₹ 175
    Gain % = 25%
    Required C.P. = ₹
    100
    × 175 = ₹ 140
    125

    Using the given formula :
    Here, r = 25% , D = 12.5% , M.P. = ₹ 200 , C.P. = ?
    M.P.
    =
    100 + r
    C.P.100 − D

    Correct Option: D

    Given that , marked price of an article = ₹ 200

    Discount = 12
    1
    % =
    25
    %
    22

    After discount , S.P. = ₹ 200 × 87.5 = ₹ 175
    Gain % = 25%
    Required C.P. = ₹
    100
    × 175 = ₹ 140
    125

    Using the given formula :
    Here, r = 25% , D = 12.5% , M.P. = ₹ 200 , C.P. = ?
    M.P.
    =
    100 + r
    C.P.100 − D

    200
    =
    100 + 25
    C.P.100 − 12.5

    C.P. =
    200 × 87.5
    125

    C.P. = ₹ 140



  1. A trader wishes to gain 20% after allowing 10% discount on the marked price to his customers. At what per cent higher than the cost price must he marks his goods ?









  1. View Hint View Answer Discuss in Forum

    Let the CP be ₹ 100. Then SP on 20% gain = ₹ 120
    Let the marked price be y.
    Then, ( 100 - 10 )% of y = ₹ 120
    ⇒ 90% of y = ₹ 120

    ⇒  y =
    120 × 100
    =
    400
    903

    Correct Option: B

    Let the CP be ₹ 100. Then SP on 20% gain = ₹ 120
    Let the marked price be y.
    Then, ( 100 - 10 )% of y = ₹ 120
    ⇒ 90% of y = ₹ 120

    ⇒  y =
    120 × 100
    =
    400
    903

    y = 133
    1
    3

    It is 33
    1
    % higher than the CP.
    3