## Discount

#### Discount

1. Two successive discounts of 20% and 20% are equivalent to a single discount of
1. 42%
2. 40%
3. 36%
4. 34%

1. Given, r1 = 20% and r2 = 20%
∴ Single discount equal to r1 and r2
= (r1 + r2 - r1 x r2) / 100 %

##### Correct Option: C

Given, r1 = 20% and r2 = 20%
∴ Single discount equal to r1 and r2
= (r1 + r2 - r1 x r2) / 100 %
= (20 + 20 - 20 x 20) / 100
= 40 - 4 = 36%

1. On a 20 % discount sale, an article costs 596 . What was the original price of the article ?
1. ₹ 720
2. ₹ 735
3. ₹ 745
4. ₹ 775

1. Let the original price of be N .
∴ At discount of 20% article costs ₹ 596
∴ 596 = (80 x N)/100

##### Correct Option: C

Let the original price of be N .
∴ At discount of 20% article costs ₹ 596
∴ 596 = (80 x N)/100
⇒ N = (596 x 100)/80
∴ N = 745
∴ original price = ₹ 745

1. If an electricity bill is paid before due date, one gets a reduction of 4 % on the amount of the bill . By paying the bill before due date, a person got a reduction of ₹ 13 . The amount of his electricity bill was
1. ₹ 125
2. ₹ 225
3. ₹ 325
4. ₹ 425

1. Let amount of electricity bill = ₹ N
∴ 4% of N = 13
⇒ (4 x N)/100 = 13

##### Correct Option: C

Let amount of electricity bill = ₹ N
∴ 4% of N = 13
⇒ (4 x N)/100 = 13
⇒ N = 13 x 25 = ₹ 325

1. Successive discounts of 10%, 20% and 30% is equivalent to single discount of?
1. 60%
2. 49.6%
3. 40.5%
4. 36%

1. Here, r1 = 10 %, r2 = 20% and r3 = 30%
∴ Required discount
= [1 - (1 - r1/100) (1 - r2/100) (1 - r3/100)] x 100%

##### Correct Option: B

Here, r1 = 10 %, r2 = 20% and r3 = 30%
∴ Required discount
= [1 - (1 - r1/100) (1 - r2/100) (1 - r3/100)] x 100%
= [1 - (1 -10/100) (1 - 20/100) (1 - 30/100)] x 100%
= {1 - (9/10) x (4/5) x (7/10)} x 100%
= (1 - 0.504) x 100% = 49.6%

1. A shopkeeper has announced 14% rebate on marked price of an article. If the selling price of the article is ₹ 645, then the marked price of the article will be?
1. ₹ 800
2. ₹ 810
3. ₹ 750
4. ₹ 775

1. Let the marked price of item = ₹ N
∴ {(100 - 14) /100 } of N = 645

##### Correct Option: C

Let the marked price of item = ₹ N
∴ {(100 - 14) /100 } of N = 645
⇒ N = (645 x 100)/86 = ₹ 750