Discount
- A tradesman marks his goods at 20% above the cost price. He allows his customers a discount of 8% on marked price. Find out his profit %.
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Suppose C.P. = 100
On 20% above S.P. = 120On discount of 8% = 120 − 120 × 8 100 New S.P. = 120 − 48 = 120 − 9.6 = 110.4 5
Gain = 110.4 – 100 = 10.4%
2nd method to solve this question
Here, r = 20%, r1 = 8%Profit or loss = r ×(100 − r1) −r1 100 Profit or loss = 20 ×(100 − 8) − 8 100
Correct Option: B
Suppose C.P. = 100
On 20% above S.P. = 120On discount of 8% = 120 − 120 × 8 100 New S.P. = 120 − 48 = 120 − 9.6 = 110.4 5
Gain = 110.4 – 100 = 10.4%
2nd method to solve this question
Here, r = 20%, r1 = 8%Profit or loss = r ×(100 − r1) −r1 100 Profit or loss = 20 ×(100 − 8) − 8 100 Profit or loss = 20 × 92 − 8 100
= 18.4 – 8
Required Profit or loss = 10.4% profit
- Two shopkeepers announce the same price of Rs. 700 for a sewing machine. The first offers successive discounts of 30% and 6% while the second offers successive discounts of 20% and 16%. The difference in their selling price is :
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For the first shopkeeper,
Single equivalent discount for two successive discounts of 30% and 6%= 30 + 6 − 30 × 6 % 100
= ( 36 –1.8 ) % = 34.2 %
∴ S.P. of sewing machine = ( 100 – 34.2 ) % of Rs. 700
For the second shopkeeper,
Single equivalent discount= 20 + 16 − 20 × 16 % 100
= ( 36 – 3.2 )% = 32.8 %
∴ S.P. of sewing machine = 700 × ( 100 – 32.8 ) %Correct Option: A
For the first shopkeeper,
Single equivalent discount for two successive discounts of 30% and 6%= 30 + 6 − 30 × 6 % 100
= ( 36 –1.8 ) % = 34.2 %
∴ S.P. of sewing machine = ( 100 – 34.2 ) % of Rs. 700= Rs. 700 × 65.8 = Rs. 460.6 100
For the second shopkeeper,
Single equivalent discount= 20 + 16 − 20 × 16 % 100
= ( 36 – 3.2 )% = 32.8 %
∴ S.P. of sewing machine = 700 × ( 100 – 32.8 ) %= Rs. 700 × 67.8 = Rs. 470.4 100
Required difference = Rs. (470.4 – 460.6) = Rs. 9.8
Alternate method to find the difference
Difference between single equivalent discounts = ( 34.2 – 32.8 ) % = 1.4 %∴ Difference of S.P. = Rs. 700 × 1.4 = Rs. 9.8 100
- When a discount of 20% is given on a sweater, the profit is 28%. If the discount is 14%, then the profit is
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Let the C.P. of sweater be Rs. 100 and its marked price be Rs. x.
According to the question,x × 80 = 128 100 ⇒ x × 4 = 128 5 Correct Option: D
Let the C.P. of sweater be Rs. 100 and its marked price be Rs. x.
According to the question,x × 80 = 128 100 ⇒ x × 4 = 128 5 ⇒ x = 128 × 5 = Rs. 160 4
When discount = 14%, then
S.P. of sweater
= 160 × (100 – 1(4)%= 160 × 86 = Rs. 137.6 100
∵ C.P. = Rs. 100
∴ Profit per cent = 37.6%
- A merchant changed his trade discount from 25% to 15%. This would increase selling price by
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Let us assume the price of article be Rs. M.
∴ S.P. at 25% discount = Rs. 75M = Rs. 3M 100 4 S.P. at 15% discount = Rs. 85M = Rs. 17M 100 20 Increased Price = Rs. 17M − 3M 20 4 Increased Price = Rs. 17M − 15M = Rs. M 20 10
Correct Option: C
Let us assume the price of article be Rs. M.
∴ S.P. at 25% discount = Rs. 75M = Rs. 3M 100 4 S.P. at 15% discount = Rs. 85M = Rs. 17M 100 20 Increased Price = Rs. 17M − 3M 20 4 Increased Price = Rs. 17M − 15M = Rs. M 20 10 ∴ Percentage increase = M × 100 10 3M 4 ∴ Percentage increase = M × 4 × 100 10 3M ∴ Percentage increase = 40 = 13 1 % 3 3
- A trader marked the selling price of an article at 10% above the cost price. At the time of selling, he allows certain discount and suffers a loss of 1%. He allowed the discount of :
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Let C.P. be 100
Marked price = 110
∴ p% of 110 = 11⇒ p = 11 × 100 = 10% 100
2nd method to solve this question.
Here, loss % = 1%, r = 10%, r1 = p%loss % = r × (100 − r1) − r1 100 −1 = 100 × (100 − p) − p 100
Correct Option: B
Let C.P. be 100
Marked price = 110
∴ p% of 110 = 11⇒ p = 11 × 100 = 10% 100
2nd method to solve this question.
Here, loss % = 1%, r = 10%, rr1 = p%loss % = r × (100 − r1) − r1 100 −1 = 100 × (100 − p) − p 100
(–ve sign for loss)
–100 = 1000 – 10p – 100p
110p = 1100
p = 10%
⇒ r1 = 10%