Discount


  1. If the cost of an article is Rs. P after two successive reductions of 20% and 25%, the original price of the article was
    1. Rs.
      5P
      3
    2. Rs.
      4P
      5
    3. Rs.
      3P
      5
    4. Rs.
      5P
      4

  1. View Hint View Answer Discuss in Forum

    Let us assume the price of article = Rs. A
    According to the question,

    P =
    A x (100 − 20)
    ×
    100 − 25
    100100

    ⇒ P = A ×
    80
    ×
    75
    100100

    Correct Option: A

    Let us assume the price of article = Rs. A
    According to the question,

    P =
    A x (100 − 20)
    ×
    100 − 25
    100100

    ⇒ P = A ×
    80
    ×
    75
    100100

    ⇒ P = A ×
    4
    ×
    3
    =
    3A
    545

    ⇒  A = Rs.
    5
    P
    3


  1. A dealer buys a table listed at Rs. 1,500 and gets successive discounts of 20% and 10%. He spends Rs. 20 on transportation and sells it at a profit of 20%. Find the selling price of the table.
    1. Rs. 1,420
    2. Rs. 1,300
    3. Rs. 1,320
    4. Rs. 1,380

  1. View Hint View Answer Discuss in Forum

    Single equivalent discount for 20% and 10%

    = 20 + 10 −
    20 × 10
    % = 28%
    100

    ∴  C.P. = (100 – 28)% of 1500
    ∴  C.P =
    1500 × 72
    = Rs. 1080
    100

    Actual C.P. = Rs. (1080 + 20) = Rs. 1100

    Correct Option: C

    Single equivalent discount for 20% and 10%

    = 20 + 10 −
    20 × 10
    % = 28%
    100

    ∴  C.P. = (100 – 28)% of 1500
    ∴  C.P =
    1500 × 72
    = Rs. 1080
    100

    Actual C.P. = Rs. (1080 + 20) = Rs. 1100

    ∴  S.P. on 20% profit =
    1100 × 120
    = Rs. 1320
    100



  1. Allowing 20 % and 15 % successive discounts, the selling price of an article becomes Rs. 3,060; then the marked price will be
    1. Rs. 4,000
    2. Rs. 4,400
    3. Rs. 5,000
    4. Rs. 4,500

  1. View Hint View Answer Discuss in Forum

    Let us assume the Marked price of article = Rs. M
    According to the question,

    M ×
    80
    ×
    85
    = 3060
    100100

    Alternate method to solve this question :

    According to given question.
    Here, S.P. = Rs. 3060, M.P. = ?, D1 = 20%, D2 = 15%

    S.P = M.P
    100 − D1
    100 − D2
    100100
    3060 = M.P.
    100 − 20
    100 − 15
    100100


    Correct Option: D

    Let us assume the Marked price of article = Rs. M
    According to the question,

    M ×
    80
    ×
    85
    = 3060
    100100

    ⇒  M =
    3060 × 100 × 100
    80 × 85

    M = Rs. 4500
    Alternate method to solve this question :
    According to given question.
    Here, S.P. = Rs. 3060, M.P. = ?, D1 = 20%, D2 = 15%

    S.P = M.P
    100 − D1
    100 − D2
    100100

    3060 = M.P.
    100 − 20
    100 − 15
    100100
    3060 = M.P.
    80
    ×
    85
    100100

    M.P. =
    3060 × 10000
    80 × 85

    M.P. = Rs. 4500


  1. The difference between a discount of 30% and two successive discounts of 20% and 10% on the marked price of an article is Rs. 144. The marked price of the article is
    1. Rs. 7,200
    2. Rs. 7,400
    3. Rs. 7,500
    4. Rs. 7,000

  1. View Hint View Answer Discuss in Forum

    Let the marked price of article be Rs. M.

    Single equivalent discount for X % and Y % = x + y −
    xy
    %
    100

    Single equivalent discount for 20% and 10% = 20 + 10 −
    20 × 10
    % = 28%
    100

    According to the question,

    30% of M – 28% of M = 144
    Solve this equation further to calculate the Marked price of the article.

    Correct Option: A

    Let the marked price of article be Rs. M.

    Single equivalent discount for X % and Y % = x + y −
    xy
    %
    100

    Single equivalent discount for 20% and 10% = 20 + 10 −
    20 × 10
    % = 28%
    100

    According to the question,

    30% of M – 28% of M = 144
    ⇒ 
    M × 2
    = 144
    100

    ⇒  M =
    144 × 100
    2

    ⇒  M = Rs. 7200



  1. An article is marked at ₹ 5,000. The shopkeeper allows successive discounts of x%, y%, z% on it. The net selling price is
    1. (100 − x)(100 + y)(100 + z)
      200
    2. (100 + x)(100 + y)(100 − z)
      200
    3. (100 − x)(100 − y)(100 − z)
      200
    4. (100 − x)(100 + y)(100 − z)
      200

  1. View Hint View Answer Discuss in Forum

    Required S.P = 5000 ×
    (100 − x)
    ×
    (100 − y)
    ×
    (100 − z)
    100100100

    Correct Option: C

    Required S.P = 5000 ×
    (100 − x)
    ×
    (100 − y)
    ×
    (100 − z)
    100100100

    Required S.P = ₹
    (100 − x)(100 − y)(100 − z)
    200