Discount
- Which of the following successive discounts is better to a customer?
(a) 20%, 15%, 10% or
(b) 25%, 12%, 8% ?
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(a) Single equivalent discount for 20% and 15%
= 20 + 15 − 20 × 15 % = 32% 100
(b) Single equivalent discount for 25% and 12%= 25 + 12 − 25 × 12 % = 34% 100
Alternate method to solve this question :
Case I.
D1 = 20%, D2 = 15%, D3 = 10%Equivalent discount = 100 − 100 − D1 100 − D2 100 − D3 × 100 100 100 100
Case II.
D1 = 25%, D2 = 12%, D3 = 8%Equivalent discount = 100 − 100 − D1 100 − D2 100 − D3 × 100 100 100 100 Correct Option: B
(a) Single equivalent discount for 20% and 15%
= 20 + 15 − 20 × 15 % = 32% 100
Single equivalent discount for 32% and 10%= 32 + 10 − 32 × 10 % = 38.8% 100
(b) Single equivalent discount for 25% and 12%= 25 + 12 − 25 × 12 % = 34% 100
Single equivalent discount for 34% and 8%= 34 + 8 − 34 × 8 % = 42 – 2.72 = 39.28% 100
Alternate method to solve this question :
Case I.
D1 = 20%, D2 = 15%, D3 = 10%Equivalent discount = 100 − 100 − D1 100 − D2 100 − D3 × 100 100 100 100 Equivalent discount = 100 − 100 − 20 100 − 15 100 − 10 × 100 100 100 100 Equivalent discount = 100 − 80 × 85 × 90 × 100 100 100 100
Equivalent discount = 100 – 61.2 = 38.8%
Case II.
D1 = 25%, D2 = 12%, D3 = 8%Equivalent discount = 100 − 100 − D1 100 − D2 100 − D3 × 100 100 100 100 Equivalent discount = 100 − 100 − 25 100 − 12 100 − 8 × 100 100 100 100 Equivalent discount = 100 − 75 × 88 × 92 × 100 100 100 100
Equivalent discount = 100 – 60.72 = 39.28%
⇒ Case II is better than Case I.
- An article is marked at ₹ 5,000. The shopkeeper allows successive discounts of x%, y%, z% on it. The net selling price is
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Required S.P = 5000 × (100 − x) × (100 − y) × (100 − z) 100 100 100 Correct Option: C
Required S.P = 5000 × (100 − x) × (100 − y) × (100 − z) 100 100 100 Required S.P = ₹ (100 − x)(100 − y)(100 − z) 200
- The difference between a discount of 30% and two successive discounts of 20% and 10% on the marked price of an article is Rs. 144. The marked price of the article is
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Let the marked price of article be Rs. M.
Single equivalent discount for X % and Y % = x + y − xy % 100 Single equivalent discount for 20% and 10% = 20 + 10 − 20 × 10 % = 28% 100
According to the question,
30% of M – 28% of M = 144
Solve this equation further to calculate the Marked price of the article.Correct Option: A
Let the marked price of article be Rs. M.
Single equivalent discount for X % and Y % = x + y − xy % 100 Single equivalent discount for 20% and 10% = 20 + 10 − 20 × 10 % = 28% 100
According to the question,
30% of M – 28% of M = 144⇒ M × 2 = 144 100 ⇒ M = 144 × 100 2
⇒ M = Rs. 7200
- Allowing 20 % and 15 % successive discounts, the selling price of an article becomes Rs. 3,060; then the marked price will be
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Let us assume the Marked price of article = Rs. M
According to the question,M × 80 × 85 = 3060 100 100
Alternate method to solve this question :
According to given question.
Here, S.P. = Rs. 3060, M.P. = ?, D1 = 20%, D2 = 15%S.P = M.P 100 − D1 100 − D2 100 100 3060 = M.P. 100 − 20 100 − 15 100 100
Correct Option: D
Let us assume the Marked price of article = Rs. M
According to the question,M × 80 × 85 = 3060 100 100 ⇒ M = 3060 × 100 × 100 80 × 85
M = Rs. 4500
Alternate method to solve this question :
According to given question.
Here, S.P. = Rs. 3060, M.P. = ?, D1 = 20%, D2 = 15%S.P = M.P 100 − D1 100 − D2 100 100 3060 = M.P. 100 − 20 100 − 15 100 100 3060 = M.P. 80 × 85 100 100 M.P. = 3060 × 10000 80 × 85
M.P. = Rs. 4500
- In order that there may be a profit of 20% after allowing a discount of 10% on the marked price, the cost price of an article has to be increased by
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Let MP = ₹ N
∴ SP = N x (100 - 10)/100 = ₹ 9N/10
∴ CP = (9N/10) x [100/(100 + 20)] = ₹ 3N/4
Thus, CP has to be increased by = [(N - 3N/4) / (3N/4)] x 100%Correct Option: C
Let MP = ₹ N
∴ SP = N x (100 - 10)/100 = ₹ 9N/10
∴ CP = (9N/10) x [100/(100 + 20)] = ₹ 3N/4
Thus, CP has to be increased by = [(N - 3N/4) / (3N/4)] x 100%
= [(N/4) / (3N/4)] x 100 %
= 331/3 %
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