Discount
- A shopkeeper allows a discount of 4% on his article. If cost price of the article is ₹ 100 and he wants to get a profit of 20%. Then, its marked price will be
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∵ Cost price of article = ₹ 100
∴ Selling price of the article for 20% profit
= 100 x (100 + 20)/100 = ₹ 120
Hence, marked price of the article for 4% discount
= 120 x 100/(100 - 4)Correct Option: C
∵ Cost price of article = ₹ 100
∴ Selling price of the article for 20% profit
= 100 x (100 + 20)/100 = ₹ 120
Hence, marked price of the article for 4% discount
= 120 x 100/(100 - 4)
= 120 x 100/96
= ₹ 125
- A shopkeeper allows 23% commission on his advertised price and still makes a profit of 10%. If he gains ₹ 56 on one item, his advertised price of the item (in ₹) is
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Advertised price of the item = ₹ N
∴ Commission on advertised price of the article = ₹ (N x 23)/100
Price after commission = N - (23N/100) = ₹ 77N/100Correct Option: D
Advertised price of the item = ₹ N
∴ Commission on advertised price of the article = ₹ (N x 23)/100
Price after commission = N - (23N/100) = ₹ 77N/100
∴ CP of the item = [(77N/100) x 100]/(100 + 10) = 77N/110 = ₹ 7N/10
Profit = 77N/100 - 7N/10 = ₹ 7N/100
⇒ 56 = 7N/100
∴ N = (56 x 100)/7 = ₹ 800
- The difference between a discount of 30% on ₹ 2000 and two successive discounts of 25% and 5% on the same amount is
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Single equivalent discount per cent to 25% and 5%
= r1 + r2 - (r1 . r2)/100 %Correct Option: C
Single equivalent discount per cent to 25% and 5%
= r1 + r2 - (r1 . r2)/100 %
= 25 + 5 - (25 x 5)/100
= 30 - 1.25
= 28.78 %
∴ Required difference = [(30 - 28.75) x 2000]/100
= 1.25 x 2000/100 = ₹ 25
- If the price of an item is increased by 30 % and then allows two successive discounts of 10 % and 10 % . In last the price of an item is?
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Let the cost price of item = ₹ N
∴ Marked price of item = N x (100 + 30)/100 = ₹ 13N/10
Selling price of the item after two successive discount = (13N/10) x[ (100 - 10)/100 x (100 - 10)/100]
= (13N/10) x (90/100) x (90/100) = ₹ 1053N/1000Correct Option: B
Let the cost price of item = ₹ N
∴ Marked price of item = N x (100 + 30)/100 = ₹ 13N/10
Selling price of the item after two successive discount = (13N/10) x[ (100 - 10)/100 x (100 - 10)/100]
= (13N/10) x (90/100) x (90/100) = ₹ 1053N/1000
Increment in the price of item = [{(1053N/1000) - N} / N] x 100 %
= 53/10 %
= 5.3 %
- A shopkeeper sells not books at the rate of ₹ 457 each and earns a commission of 4% He also sells pencil boxes at the rate of ₹ 80 each and earns a commission of 20%. How much amount of commission will he he earn in two weeks, if he sells 10 notebooks and 6 pencil boxes a boy ?
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∴ S.P of the notebook = ₹457
∴ Commission on one notebook = ₹ (4 x 457)/100
and commission on 10 notebooks = 10 x (4 x 457)/100 = ₹ 18280
Now,S.P of the pencil box = ₹ 80
∴ Commission on 1 pencil box = ₹ (80 x 20)/100
Commission on 6 pencil boxes = (80 x 20 x 6)/100 = ₹ 96
Hence ,total commission of 1 day = (182.80 + 96 ) = ₹ 278.80Correct Option: E
∴ S.P of the notebook = ₹457
∴ Commission on one notebook = ₹ (4 x 457)/100
and commission on 10 notebooks = 10 x (4 x 457)/100 = ₹ 18280
Now,S.P of the pencil box = ₹ 80
∴ Commission on 1 pencil box = ₹ (80 x 20)/100
Commission on 6 pencil boxes = (80 x 20 x 6)/100 = ₹ 96
Hence ,total commission of 1 day = (182.80 + 96 ) = ₹ 278.80
Thus, total commission of 2 weeks = 278.80 x 14 = ₹ 3903.20
