266. Two successive discounts of 10% and 20% are equivalent to a single discount of

1. 1. 28%

   
   
   

   2. 27%

   
   
   

   3. 25%

   
   
   

   4. 30%

   
   
   

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1. View Hint View Answer Discuss in Forum

   Single equivalent discount
   

   =		x + y −	xy		%
   			100

   Correct Option: A

   Single equivalent discount
   

   =		x + y −	xy		%
   			100

   
   

   =		20 + 10 −	20 × 10		%
   			100

   
   = (30 – 2)% = 28%

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267. The price of a chair is Rs. 500. It has been sold at two successive discounts of 10 % each. What is its selling price?

1. 1. Rs. 400

   
   
   

   2. Rs. 405

   
   
   

   3. Rs. 415

   
   
   

   4. Rs. 425

   
   
   

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1. View Hint View Answer Discuss in Forum

   Single equivalent discount for 10 % and 10 %
   

   =		10 + 10 −	10 × 10		% = 19%
   			100

   
   ∴  S.P. of chair = (100 – 19)% of Rs. 500

   Correct Option: B

   Single equivalent discount for 10 % and 10 %
   

   =		10 + 10 −	10 × 10		% = 19%
   			100

   
   ∴  S.P. of chair = (100 – 19)% of Rs. 500
   

   ∴  S.P. of chair = Rs.		500 × 81		= Rs. 405
   		100

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268. Two consecutive discounts x% and y% are equivalent to the single discount of

1. 1. 	x − y +	xy		%
      		100

   
   
   

   2. 	x + y +	xy		%
      		100

   
   
   

   3. 	x − y −	xy		%
      		100

   
   
   

   4. 	x + y −	xy		%
      		100

   
   
   

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1. View Hint View Answer Discuss in Forum

   Single equivalent discount for consecutive discounts of x% and y%
   

   =		x + y −	xy		%
   			100

   Correct Option: D

   As we know that ,
   

   Equivalent single discount =		D1 + D2 −	D1 × D2		%
   			100

   
   Single equivalent discount for consecutive discounts of x% and y%
   

   =		x + y −	xy		%
   			100

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269. A shopkeeper marks his goods 20% above cost price, but allows 30% discount for cash. His net loss is :

1. 1. 8%

   
   
   

   2. 10%

   
   
   

   3. 16%

   
   
   

   4. 20%

   
   
   

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1. View Hint View Answer Discuss in Forum

   Let the cost price be p Mark Price
   

   =		1 +	20		p = 1.2p
   			100

   
   

   Cash price =		1 −	30		1.2p
   			100

   
   = 0.7 × 1.2p = 0.84p
   Net Loss = p – 0.84p = 0.16p
   

   ∴  Net loss% =	0.16p	× 100 = 16%
   	p

   
   2nd method to solve this question.
   Here, r = 20%, r₁ = 30%
   

   Profit or loss =	r ×(100 − r1)	−r1
   	100

   
   

   Correct Option: C

   Let the cost price be p Mark Price
   

   =		1 +	20		p = 1.2p
   			100

   
   

   Cash price =		1 −	30		1.2p
   			100

   
   = 0.7 × 1.2p = 0.84p
   Net Loss = p – 0.84p = 0.16p
   

   ∴  Net loss% =	0.16p	× 100 = 16%
   	p

   
   2nd method to solve this question.
   Here, r = 20%, r₁ = 30%
   

   Profit or loss =	r ×(100 − r1)	−r1
   	100

   
   

   Profit or loss =	20 × (100 − 30)	− 30
   	100

   
   Profit or loss= 14 – 30 = –16%
   Required Profit or loss = 16% loss

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270. A shopkeeper marks his sarees at 20% above the cost price and allows the purchaser a discount of 10% for cash buying. What profit percent does he make?

1. 1. 18%

   
   
   

   2. 12%

   
   
   

   3. 10%

   
   
   

   4. 8%

   
   
   

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1. View Hint View Answer Discuss in Forum

   As we know that ,
   

   Gain % = a − b −	a × b
   	100

   
   

   Gain % = 20 − 10 −	20 × 10
   	100

   
   2nd method to solve this question .
   Here, r = 20%, r₁ = 10%
   

   Correct Option: D

   As we know that ,
   

   Gain % = a − b −	a × b
   	100

   
   

   Gain % = 20 − 10 −	20 × 10
   	100

   
   2nd method to solve this question .
   Here, r = 20%, r₁ = 10%
   

   Profit or loss =	r × (100 − r1)	− r1
   	100

   
   

   Profit or loss =	20 × (100 − 10)	− 10
   	100

   
   Required Profit or loss = 18 – 10 = 8% profit.

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