Discount


  1. The selling price of a video game is ₹ 740 and the discount allowed is 7.5%. The marked price of the video game is :









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    Here , The selling price of a video game = ₹ 740 , discount = 7.5%

    Marked price =
    100
    × 740
    (100 − 7.5)

    Marked price =
    740 × 100
    = ₹ 800
    92.5

    Second method :
    Here, S.P. = ₹ 740, D = 7.5%, M.P. = ?
    Using the given formula ,
    M.P. =
    S.P. × 100
    100 − D

    Correct Option: C

    Here , The selling price of a video game = ₹ 740 , discount = 7.5%

    Marked price =
    100
    × 740
    (100 − 7.5)

    Marked price =
    740 × 100
    = ₹ 800
    92.5

    Second method :
    Here, S.P. = ₹ 740, D = 7.5%, M.P. = ?
    Using the given formula ,
    M.P. =
    S.P. × 100
    100 − D

    M.P. =
    740 × 100
    100 − 7.5

    M.P. =
    74000
    = ₹ 800
    92.5


  1. A fan is listed at ₹ 150 and a discount of 20% is given. Then the selling price is









  1. View Hint View Answer Discuss in Forum

    Given that , Marked price of fan = ₹ 150 , discount = 20%

    S.P. of the fan =
    150 × 80
    = ₹ 120
    100

    We can find the required answer with the help of given formula :
    M.P. = ₹ 150, D = 20%, S.P. = ?
    M.P. =
    S.P. × 100
    100 − D

    Correct Option: C

    Given that , Marked price of fan = ₹ 150 , discount = 20%

    S.P. of the fan =
    150 × 80
    = ₹ 120
    100

    We can find the required answer with the help of given formula :
    M.P. = ₹ 150, D = 20%, S.P. = ?
    M.P. =
    S.P. × 100
    100 − D

    150 =
    S.P. × 100
    100 − 20

    S.P. =
    150 × 80
    100

    ∴ S.P. = ₹ 120



  1. If a dining table with marked price ₹ 6,000 was sold to a customer for 5,500, then the rate of discount allowed on the table is









  1. View Hint View Answer Discuss in Forum

    Discount = 6000 – 5500 = ₹ 500
    If discount = x%, then

    6000 × x
    = 500
    100

    ⇒ x =
    500
    =
    25
    = 8
    1
    %
    6033

    Second method :
    M.P. = ₹ 6000
    S.P. = ₹ 5500
    Discount % =
    M.P. − S.P.
    × 100
    M.P.

    =
    6000 − 5500
    × 100
    6000

    =
    500 − 100
    6000

    8
    1
    %
    3

    Correct Option: C

    Discount = 6000 – 5500 = ₹ 500
    If discount = x%, then

    6000 × x
    = 500
    100

    ⇒ x =
    500
    =
    25
    = 8
    1
    %
    6033

    Second method :
    M.P. = ₹ 6000
    S.P. = ₹ 5500
    Discount % =
    M.P. − S.P.
    × 100
    M.P.

    =
    6000 − 5500
    × 100
    6000

    =
    500 − 100
    6000

    8
    1
    %
    3


  1. A washing machine is sold at a discount of 30%. If a man buys it for ₹ 6,580, its list price is









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    Marked price =
    6580 × 100
    = ₹ 9400
    70

    Second method :
    D = 30%, S.P. = 6580, M.P. = ?
    M.P. =
    S.P. × 100
    100 − D


    =
    6580 × 100
    100 − 30


    =
    658000

    = ₹ 9400
    70

    Correct Option: C

    Marked price =
    6580 × 100
    = ₹ 9400
    70

    Second method :
    D = 30%, S.P. = 6580, M.P. = ?
    M.P. =
    S.P. × 100
    100 − D


    =
    6580 × 100
    100 − 30


    =
    658000

    = ₹ 9400
    70



  1. An article marked ₹ 800 is offered at ₹ 736 in the off season. The rate of discount offered is :









  1. View Hint View Answer Discuss in Forum

    Discount = 800 – 736 = ₹ 64


    ∴  Discount percent =
    64

    ×100 = 8%
    800

    Correct Option: D

    Discount = 800 – 736 = ₹ 64


    ∴  Discount percent =
    64

    ×100 = 8%
    800