Discount
- A shopkeeper lists the price of an article as ₹ 500. But he gives a certain discount which allows the buyer to pay ₹ 500 for the article including 10% sales tax. The rate of discount is
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Let the S.P. be x (without tax).
∴ x + x × 10 = 500 100 ⇒ 11x = 500 ⇒ x = ₹ 5000 10 11 ∴ Discount = 500 − 5000 11 = 500 11 Discount per cent = 500 × 100 11 × 500 = 100 % or 9 1 % 11 11 Correct Option: C
Let the S.P. be x (without tax).
∴ x + x × 10 = 500 100 ⇒ 11x = 500 ⇒ x = ₹ 5000 10 11 ∴ Discount = 500 − 5000 11 = 500 11 Discount per cent = 500 × 100 11 × 500 = 100 % or 9 1 % 11 11
- With a 5 % discount on the cost of sugar, a buyer could purchase 2 kg more sugar for ₹ 608. Selling price of sugar is :
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Let the original S.P. of sugar be x per kg.
S.P. after discount = ₹ 95x per kg 100 = ₹ 19x per kg 20 ∴ 608 − 608 = 2 19x/20 x ⇒ 608 20 − 1 = 2 19x x
Let the original S.P. of sugar be x per kg.⇒ 608 = 2 ⇒ x = 608 = ₹ 16 19x 19 × 2 S.P. after discount = ₹ 95x per kg 100 = ₹ 19x per kg 20 ∴ 608 − 608 = 2 19x/20 x ⇒ 608 20 − 1 = 2 19x x ⇒ 608 = 2 ⇒ x = 608 = ₹ 16 19x 19 × 2 Correct Option: D
Let the original S.P. of sugar be x per kg.
S.P. after discount = ₹ 95x per kg 100 = ₹ 19x per kg 20 ∴ 608 − 608 = 2 19x/20 x ⇒ 608 20 − 1 = 2 19x x ⇒ 608 = 2 ⇒ x = 608 = ₹ 16 19x 19 × 2
- During a month-long annual sale, a shopkeeper sells his goods at a discount of 50%. But in the last week, he offers an additional discount of 40%. If the original price of a shirt is ₹ x, then the price, (in rupees) during the last week of the sale will be
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Single equivalent discount = 50 + 40 − 50 × 40 % = 70% 100
∴ Required price of shirt = 30% of xCorrect Option: C
Single equivalent discount = 50 + 40 − 50 × 40 % = 70% 100
∴ Required price of shirt = 30% of x
- Ramesh bought 10 cycles for ₹ 500 each. He spent ₹ 2,000 on the repair of all cycles. He sold five of them for ₹ 750 each and the remaining for ₹ 550 each. Then the total gain or loss % is
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Total actual C.P.
= ₹ (500 × 10 + 2000) = ₹ 7000
Total S.P.
= ₹ (5 × 750 + 5× 550)
= ₹ (3750 + 2750) = ₹ 6500
Loss = 7000 – 6500 = ₹ 500Loss percent = 500 × 100 = 50 = 7 1 % 7000 7 7 Correct Option: D
Total actual C.P.
= ₹ (500 × 10 + 2000) = ₹ 7000
Total S.P.
= ₹ (5 × 750 + 5× 550)
= ₹ (3750 + 2750) = ₹ 6500
Loss = 7000 – 6500 = ₹ 500Loss percent = 500 × 100 = 50 = 7 1 % 7000 7 7
- A fan is listed at ₹ 1,400 and the discount offered is 10%. What additional discount must be given to bring the net selling price to ₹ 1,200 ?
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Marked price of the fan = ₹ 1400
SP after allowing a discount of 10% = 90% of 1400= 1400 × 90 = ₹ 1260 100
Second discount = ₹ (1260 – 1200 ) = ₹ 60
Let the second discount be x%.
∴ x% of 1260 = 60⇒ x = 60 × 100 = 100 = 4 16 % 1260 21 21 Correct Option: C
Marked price of the fan = ₹ 1400
SP after allowing a discount of 10% = 90% of 1400= 1400 × 90 = ₹ 1260 100
Second discount = ₹ (1260 – 1200 ) = ₹ 60
Let the second discount be x%.
∴ x% of 1260 = 60⇒ x = 60 × 100 = 100 = 4 16 % 1260 21 21