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By giving a discount of 10% on the marked price of ₹ 1100 of a cycle, a dealer gains 10%. The cost price of the cycle is :
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- ₹ 1100
- ₹ 900
- ₹ 1089
- ₹ 891
Correct Option: B
Given that , discount = 10% and marked price of cycle = ₹ 1100
Selling Price = ₹ (1100 – 10% of 1100) = ₹ (1100 – 110) = 990
Let the cost price = y
According to question ,
∴ y + 10% of y = 990
| ⇒ | = 990 | |
| 10 |
| ⇒ y = | = ₹ 900 | |
| 11 |
Second method to solve this question :
Here, r = 10% , D = 10% , M.P. = ₹ 1100 , C.P. = ?
| = | ||
| C.P. | 100 − D |
| = | ||
| C.P. | 100 − 10 |
| C.P. = | = ₹ 900 | |
| 110 |
