Speed, Time and Distance
 A man walks ‘a’ km in ‘b’ hours. The time taken to walk 200 metres is


200b hours a 
b hours 5a 
b hours a 
ab hours 200


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Man’s speed = Distance Time = a kmph b = 1000a m/hour b
∴ Time taken in walking 200 metre= 200 = b hours 1000a/b 5a Correct Option: B
Man’s speed = Distance Time = a kmph b = 1000a m/hour b
∴ Time taken in walking 200 metre= 200 = b hours 1000a/b 5a
 A train covers a distance of 10 km in 12 minutes. If its speed is decreased by 5 km/hr, the time taken by it to cover the same distance will be :

 10 minutes
 13 minutes 20 sec
 13 minutes
 11 minutes 20 sec

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Speed of train = Distance Time = 10 kmph (12/60) = 10 × 60 = 50 kmph 12
New speed = 45 kmph∴ Required time = 10 hour 45 = 2 × 60 minutes 9 = 40 minutes 3
= 13 minutes 20 secondsCorrect Option: B
Speed of train = Distance Time = 10 kmph (12/60) = 10 × 60 = 50 kmph 12
New speed = 45 kmph∴ Required time = 10 hour 45 = 2 × 60 minutes 9 = 40 minutes 3
= 13 minutes 20 seconds
 Walking at the rate of 4 km an hour, a man covers a certain distance in 3 hours 45 minutes. If he covers the same distance on cycle, cycling at the rate of 16·5 km/hour, the time taken by him is

 55.45 minutes
 54.55 minutes
 55.44 minutes
 45.55 minutes

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Distance covered on foot = 4 × 3 3 km. = 15 km. 4
∴ Time taken on cycle= Distance = 15 hour Speed 16.5 = 15 × 60 minutes = 54.55 minutes 16.5 Correct Option: B
Distance covered on foot = 4 × 3 3 km. = 15 km. 4
∴ Time taken on cycle= Distance = 15 hour Speed 16.5 = 15 × 60 minutes = 54.55 minutes 16.5
 A train starts from a place A at 6 a.m. and arrives at another place B at 4.30 p.m. on the same day. If the speed of the train is 40 km per hour, find the distance travelled by the train ?

 420 km
 230 km
 320 km
 400 km

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Time = 10 1 hours 2 = 21 hours 2
Speed = 40 kmph
Distance = Speed × Time= 40 × 21 = 420 km 2 Correct Option: A
Time = 10 1 hours 2 = 21 hours 2
Speed = 40 kmph
Distance = Speed × Time= 40 × 21 = 420 km 2
 Two men start together to walk a certain distance, one at 4 km/h and another at 3 km/h. The former arrives half an hour before the latter. Find the distance.

 8 km
 7 km
 6 km
 9 km

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If the required distance be x km, then
x − x = 1 3 4 2 ⇒ 4x − 3x = 1 12 2 ⇒ x = 1 ⇒x = 6 km 12 2
Second Method :
Here S_{1} = 4, t_{1} = xS_{2} = 3, t_{2} = x + 1 2
S_{1}t_{1} = S_{2}t_{2}4 × x = 3 x + 1 2 4x – 3x = 3 x = 3 2 2 Distance =4 × 3 = 6 kms 2 Correct Option: C
If the required distance be x km, then
x − x = 1 3 4 2 ⇒ 4x − 3x = 1 12 2 ⇒ x = 1 ⇒x = 6 km 12 2
Second Method :
Here S_{1} = 4, t_{1} = xS_{2} = 3, t_{2} = x + 1 2
S_{1}t_{1} = S_{2}t_{2}4 × x = 3 x + 1 2 4x – 3x = 3 x = 3 2 2 Distance =4 × 3 = 6 kms 2