Speed, Time and Distance


  1. Two trains, 80 metres and 120 metres long, are running at the speed of 25 km/hr and 35 km/hr respectively in the same direction on parallel tracks. How many seconds will they take to pass each other ?









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    Relative speed = 35 – 25 = 10 kmph

    =
    10 × 5
    m/sec.
    18

    Total length = 80 + 120 = 200 metres
    ∴   Required time =
    Sum of the lengths of trains
    Relative speed

    =
    200
    10 × 5
    18

    =
    200 × 18
    = 72 seconds
    10 × 5

    Correct Option: D

    Relative speed = 35 – 25 = 10 kmph

    =
    10 × 5
    m/sec.
    18

    Total length = 80 + 120 = 200 metres
    ∴   Required time =
    Sum of the lengths of trains
    Relative speed

    =
    200
    10 × 5
    18

    =
    200 × 18
    = 72 seconds
    10 × 5


  1. In a 100m race, Kamal defeats Bimal by 5 seconds. If the speed of Kamal is 18 Kmph, then the speed of Bimal is









  1. View Hint View Answer Discuss in Forum

    Time taken by Kamal

    =
    100
    = 20 seconds
    18 ×
    5
    18

    ∴   Time taken by Bimal
    = 20 + 5 = 25 seconds
    ∴  Bimal’s speed =
    100
    = 4 m/sec
    25

    =
    4 × 18
    kmph = 14.4 kmph.
    5

    Correct Option: C

    Time taken by Kamal

    =
    100
    = 20 seconds
    18 ×
    5
    18

    ∴   Time taken by Bimal
    = 20 + 5 = 25 seconds
    ∴  Bimal’s speed =
    100
    = 4 m/sec
    25

    =
    4 × 18
    kmph = 14.4 kmph.
    5



  1. A and B start at the same time with speed of 40 km/hr and 50 km/hr respectively. If in covering the journey A takes 15 minutes longer than B, the total distance of the journey is :









  1. View Hint View Answer Discuss in Forum

    Let the distance be x km

    Time taken by A =
    x
    hrs.
    40

    Time taken by B =
    x
    hrs.
    50

    Now,   
    x
    x
    =
    15
    405060

    5x − 4x
    =
    15
    20060

    ∴  x =
    15
    × 200 = 50km
    60


    Second Method :
    Distance =
    Product of speed
    × Diff. in time
    Diff. of speed

    =
    40 × 50
    ×
    15
    = 50km
    50 − 4060

    Correct Option: C

    Let the distance be x km

    Time taken by A =
    x
    hrs.
    40

    Time taken by B =
    x
    hrs.
    50

    Now,   
    x
    x
    =
    15
    405060

    5x − 4x
    =
    15
    20060

    ∴  x =
    15
    × 200 = 50km
    60


    Second Method :
    Distance =
    Product of speed
    × Diff. in time
    Diff. of speed

    =
    40 × 50
    ×
    15
    = 50km
    50 − 4060


  1. I walk a certain distance and ride back taking a total time of 37 minutes. I could walk both ways in 55 minutes. How long would it take me to ride both ways?









  1. View Hint View Answer Discuss in Forum

    Two ways walking time = 55 min    ...(i)
    One way walking + One way riding time = 37 min.     ....(ii)
    By 2 × (ii) – (i),
    2 ways riding time
    = 2×37–55 = 19 minutes

    Correct Option: B

    Two ways walking time = 55 min    ...(i)
    One way walking + One way riding time = 37 min.     ....(ii)
    By 2 × (ii) – (i),
    2 ways riding time
    = 2×37–55 = 19 minutes



  1. Rubi goes to a multiplex at the speed of 3 km/hr to see a movie and reaches 5 minutes late. If she travels at the speed of 4 km/hr she reaches 5 minutes early. Then the distance of the multiplex from her starting point is









  1. View Hint View Answer Discuss in Forum

    Distance between starting
    point and multiplex = x metre

    Time =
    Distance
    Speed

    According to the question,
    x
    x
    =
    5 + 5
    4x − 3x
    =
    1
    3460126

    ⇒  
    x
    =
    1
    ⇒ x =
    12
    = 2 km.
    1266

    Correct Option: A

    Distance between starting
    point and multiplex = x metre

    Time =
    Distance
    Speed

    According to the question,
    x
    x
    =
    5 + 5
    4x − 3x
    =
    1
    3460126

    ⇒  
    x
    =
    1
    ⇒ x =
    12
    = 2 km.
    1266