Speed, Time and Distance
 A car travels 80 km. in 2 hours and a train travels 180 km. in 3 hours. The ratio of the speed of the car to that of the train is :

 2 : 3
 3 : 2
 3 : 4
 4 : 3

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Speed = Distance Time
∴ Speed of car : Speed of train= 80 : 180 = 40 : 60 = 2 : 3 2 3 Correct Option: A
Speed = Distance Time
∴ Speed of car : Speed of train= 80 : 180 = 40 : 60 = 2 : 3 2 3
 A truck covers a distance of 550 metre in one minute where as a bus
Then the ratio of their speeds is :covers a distance of 33 km in 3 hour. 4

 1 : 3
 2 : 3
 3 : 4
 1 : 4

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Speed of truck = 550 metre 60 second = 55 m./sec. 6 Speed of bus = 33 × 1000 metre 3 × 60 × 60 second 4 = 440 m./sec. 36 ∴ Required ratio = 55 : 440 6 36
= 55 × 6 : 440
= 3 : 4Correct Option: C
Speed of truck = 550 metre 60 second = 55 m./sec. 6 Speed of bus = 33 × 1000 metre 3 × 60 × 60 second 4 = 440 m./sec. 36 ∴ Required ratio = 55 : 440 6 36
= 55 × 6 : 440
= 3 : 4
 It takes eight hours for a 600 km journey, if 120 km is done by train and the rest by car. It takes 20 minutes more, if 200 km is done by train and the rest by car. The ratio of the speed of the train to that of the car is :

 3 : 5
 3 : 4
 4 : 3
 4 : 5

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Let the speed of train be x kmph. and the speed of car be y kmph.
Time = Distance Speed
According to the question,120 + 480 = 8 x y ⇒ 15 + 60 = 1 .....(i) x y and, 200 + 400 = 25 x y 3 ⇒ 8 + 16 = 1 x y 3 ⇒ 24 + 48 = 1 .....(ii) x y
From equations (i) and (ii),⇒ 24 + 48 = 15 + 60 x y x y ⇒ 24 − 15 = 60 − 48 x x y y ⇒ 9 = 12 x y ⇒ x = 9 = 3 = 3 : 4 y 12 4 Correct Option: B
Let the speed of train be x kmph. and the speed of car be y kmph.
Time = Distance Speed
According to the question,120 + 480 = 8 x y ⇒ 15 + 60 = 1 .....(i) x y and, 200 + 400 = 25 x y 3 ⇒ 8 + 16 = 1 x y 3 ⇒ 24 + 48 = 1 .....(ii) x y
From equations (i) and (ii),⇒ 24 + 48 = 15 + 60 x y x y ⇒ 24 − 15 = 60 − 48 x x y y ⇒ 9 = 12 x y ⇒ x = 9 = 3 = 3 : 4 y 12 4
 It takes 8 hours for a 600 km journey, if 120 km is done by train and the rest by car. It takes
20 minutes more if 200 km is done by train and the rest by car. The ratio of the speed of the train to that of the car is

 2 : 3
 3 : 2
 3 : 4
 4 : 3

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Speed of train = x kmph
Speed of car = y kmph
Case I,120 + 600 − 120 = 8 x y ⇒ 120 + 480 = 8 x y ⇒ 15 + 60 = 1 ...(i) x y
Case II,200 + 400 = 8 hours 20 minutes x y ⇒ 200 + 400 = 8 1 hours x y 3 = 25 3 ⇒ 8 + 16 = 1 x y 3 ⇒ 24 + 48 = 1 .......(ii) x y ∴ 15 + 60 = 24 + 48 x y x y ⇒ 24 − 15 = 60 − 48 x x y y ⇒ 9 = 12 ⇒ x = 9 = 3 = 3 : 4 x y y 12 4 Correct Option: C
Speed of train = x kmph
Speed of car = y kmph
Case I,120 + 600 − 120 = 8 x y ⇒ 120 + 480 = 8 x y ⇒ 15 + 60 = 1 ...(i) x y
Case II,200 + 400 = 8 hours 20 minutes x y ⇒ 200 + 400 = 8 1 hours x y 3 = 25 3 ⇒ 8 + 16 = 1 x y 3 ⇒ 24 + 48 = 1 .......(ii) x y ∴ 15 + 60 = 24 + 48 x y x y ⇒ 24 − 15 = 60 − 48 x x y y ⇒ 9 = 12 ⇒ x = 9 = 3 = 3 : 4 x y y 12 4
 A certain distance is covered by a cyclist at a certain speed. If a jogger covers half the distance in double the time, the ratio of the speed of the jogger to that of the cyclist is

 1 : 4
 4 : 1
 1 : 2
 2 : 1

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Let speed of cyclist = x kmph
& Time = t hoursDistance = xt while time = 2t 2 ∴ Required ratio = xt : x 2 × 2t
= 1 : 4Correct Option: A
Let speed of cyclist = x kmph
& Time = t hoursDistance = xt while time = 2t 2 ∴ Required ratio = xt : x 2 × 2t
= 1 : 4