Speed, Time and Distance
 A man takes 6 hours 15 minutes in walking a distance and riding back to the starting place. He could walk both ways in 7 hours 45 minutes. The time taken by him to ride both ways, is

 4 hours
 4 hours 30 minutes
 4 hours 45 minutes
 5 hours

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Time taken in walking both ways = 7 hours 45 minutes ....(i)
Time taken in walking one way and riding back = 6 hours 15 minutes ....(ii)
By equation (ii) × 2 – (i), we have Time taken by the man to ride both ways
= 12 hours 30 minutes – 7 hours 45 minutes
= 4 hours 45 minutesCorrect Option: C
Time taken in walking both ways = 7 hours 45 minutes ....(i)
Time taken in walking one way and riding back = 6 hours 15 minutes ....(ii)
By equation (ii) × 2 – (i), we have Time taken by the man to ride both ways
= 12 hours 30 minutes – 7 hours 45 minutes
= 4 hours 45 minutes
 In covering a distance of 30 km, Abhay takes 2 hours more than Sameer. If Abhay doubles his speed, then he would take 1 hour less than Sameer. Abhay's speed (in km/hr) is

 5
 6
 6.25
 7.5

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Abhay’s speed = x kmph
Sameer’s speed = y kmph∴ 30 − 30 = 2 ...(i) x y and, 30 − 30 = 1 ...(ii) y 2x
On adding,30 − 30 = 3 x 2x ⇒ 60 − 30 = 3 2x ⇒ 30 = 3 ⇒ 6x = 30 2x
⇒ x = 5 kmphCorrect Option: A
Abhay’s speed = x kmph
Sameer’s speed = y kmph∴ 30 − 30 = 2 ...(i) x y and, 30 − 30 = 1 ...(ii) y 2x
On adding,30 − 30 = 3 x 2x ⇒ 60 − 30 = 3 2x ⇒ 30 = 3 ⇒ 6x = 30 2x
⇒ x = 5 kmph
 A and B started at the same time from the same place for a certain destination.
1 hour 15 minutes after A. B reached the destination inB walking at 5 of A’s speed reached the destination 6

 6 hours 45 minutes
 7 hours 15 minutes
 7 hours 30 minutes
 8 hours 15 minutes

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1 − 5 of time taken by B 6
=1 hour 15 minutes
∴ Time taken by B
= 1 hour 15 minutes × 6
=7 hours 30 minutesCorrect Option: C
1 − 5 of time taken by B 6
=1 hour 15 minutes
∴ Time taken by B
= 1 hour 15 minutes × 6
=7 hours 30 minutes
 Ram arrives at a Bank 15 minutes earlier than scheduled time if he drives his car at 42 km/hr. If he drives car at 35 km/hr he arrives 5 minutes late. The distance of the Bank from his starting point is

 70 km
 210 km
 72 km
 60 km

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Let the required distance be x km.
Difference of time = 15 + 5 = 20 minutes= 1 hour 3
According to the question,x − x = 1 ⇒ 6x − 5x = 1 35 42 3 210 3 ⇒ x = 1 210 3 ⇒ x = 210 = 70 km. 3 Correct Option: A
Let the required distance be x km.
Difference of time = 15 + 5 = 20 minutes= 1 hour 3
According to the question,x − x = 1 ⇒ 6x − 5x = 1 35 42 3 210 3 ⇒ x = 1 210 3 ⇒ x = 210 = 70 km. 3
 Two guns are fired from the same place at an interval of 6 minutes. A person approaching the place observes that 5 minutes 52 seconds have elapsed between the hearing of the sound of the two guns. If the velocity of the sound is 330 m/sec, the man was approaching that place at what speed (in km/hr) ?

 24
 27
 30
 36

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Difference of time
= 6 min. – 5 min. 52 sec.
= 8 seconds
Distance covered by man in 5 min.52 seconds
= Distance covered by sound in 8 seconds
= 330 × 8 = 2640 m.∴ Speed of man = 2640 m 5 min. 52 sec. = 2640 m/sec 352 = 2640 × 18 kmph 352 5
= 27 kmphCorrect Option: B
Difference of time
= 6 min. – 5 min. 52 sec.
= 8 seconds
Distance covered by man in 5 min.52 seconds
= Distance covered by sound in 8 seconds
= 330 × 8 = 2640 m.∴ Speed of man = 2640 m 5 min. 52 sec. = 2640 m/sec 352 = 2640 × 18 kmph 352 5
= 27 kmph