Speed, Time and Distance


  1. A boy runs 20 km in 2.5 hours. How long will he take to run 32 km at double the previous speed ?









  1. View Hint View Answer Discuss in Forum

    The boy covers 20 km in 2.5 hours.

    ⇒ Speed =
    20
    = 8 km/hr.
    2.5

    New speed = 16 km/hr
    ∴ Time =
    32
    = 2 hours.
    16

    Correct Option: A

    The boy covers 20 km in 2.5 hours.

    ⇒ Speed =
    20
    = 8 km/hr.
    2.5

    New speed = 16 km/hr
    ∴ Time =
    32
    = 2 hours.
    16


  1. A train is moving with the speed of 180 km/hr. Its speed (in metres per second) is :









  1. View Hint View Answer Discuss in Forum

    Speed = 180 kmph

    =
    180 × 5
    m/sec = 50 m/sec
    18

    ∵   1 km/hr =
    5
    m/s
    18

    Correct Option: D

    Speed = 180 kmph

    =
    180 × 5
    m/sec = 50 m/sec
    18

    ∵   1 km/hr =
    5
    m/s
    18



  1. A man riding his bicycle covers 150 metres in 25 seconds. What is his speed in km per hour ?









  1. View Hint View Answer Discuss in Forum

    Speed =
    150
    = 6 m/sec
    25

    = 6 ×
    18
    =
    108
    = 21.6 kmph
    55

    Correct Option: B

    Speed =
    150
    = 6 m/sec
    25

    = 6 ×
    18
    =
    108
    = 21.6 kmph
    55


  1. A and B travel the same distance at speed of 9 km/hr and 10 km/hr respectively. If A takes 36 minutes more than B, the distance travelled by each is









  1. View Hint View Answer Discuss in Forum

    Let the distance between A and B be x km, then

    x
    x
    =
    36
    =
    3
    910605

    ⇒ 
    x
    =
    3
    905

    ⇒ x =
    3
    × 90 = 54 km.
    5


    Second Method :
    Here, S1 = 9, t1 = x
    S2 = 10, t2 = x −
    36
    60

    S1t1 = S2t2
    9 × x = 10x −
    36
    60

    9x = 10x – 6x = 6
    Distance travelled
    = 9 × 6 = 54 km

    Correct Option: B

    Let the distance between A and B be x km, then

    x
    x
    =
    36
    =
    3
    910605

    ⇒ 
    x
    =
    3
    905

    ⇒ x =
    3
    × 90 = 54 km.
    5


    Second Method :
    Here, S1 = 9, t1 = x
    S2 = 10, t2 = x −
    36
    60

    S1t1 = S2t2
    9 × x = 10x −
    36
    60

    9x = 10x – 6x = 6
    Distance travelled
    = 9 × 6 = 54 km



  1. A person started his journey in the morning.
    At 11 a.m. he covered
    3
    of the journey and on the
    8
    same day at 4.30 p.m. he covered
    5
    of the journey.
    6

    He started his journey at









  1. View Hint View Answer Discuss in Forum

    Difference of time = 4.30 p.m – 11.a.m.

    = 5
    1
    hours =
    11
    hours
    22

    Distance covered in
    11
    hrs
    2

    =
    5
    3
    =
    20 − 9
    =
    11
    part
    682424

    ∵  
    11
    part of the journey is covered in
    11
    hours
    242

    ⇒ 
    3
    part of the journey is covered in
    8

    =
    11
    ×
    24
    ×
    3
    =
    9
    hours
    21182

    = 4
    1
    hours.
    2

    Clearly the person started at 6.30 a.m.

    Correct Option: D

    Difference of time = 4.30 p.m – 11.a.m.

    = 5
    1
    hours =
    11
    hours
    22

    Distance covered in
    11
    hrs
    2

    =
    5
    3
    =
    20 − 9
    =
    11
    part
    682424

    ∵  
    11
    part of the journey is covered in
    11
    hours
    242

    ⇒ 
    3
    part of the journey is covered in
    8

    =
    11
    ×
    24
    ×
    3
    =
    9
    hours
    21182

    = 4
    1
    hours.
    2

    Clearly the person started at 6.30 a.m.