Speed, Time and Distance
 Rahim covers a certain distance in 14 hrs 40 min. He covers one half of the distance by train at 60 km/hr. and rest half by road at 50 km/hr. The distance travelled by him is ?

 960 km.
 720 km.
 1000 km.
 800 km.

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Let the total distance be y km.
Then, (y/2) x (1/60) + (y/2) x (1/50) = 44/3Correct Option: D
Let the total distance be y km.
Then, (y/2) x (1/60) + (y/2) x (1/50) = 44/3
⇒ y/120 + y/100 = 44/3
⇒ 5y + 6y = 8800
⇒ y = 800
∴ Required distance = 800km.
 A man perform 2/15 of the total journey by rail, 9/20 by tonga and the remaining 10 km on foot. This total journey is ?

 15.6 km.
 12.8 km.
 16.4 km.
 24 km.

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Let the total journey be x km. then,
2x/15 + 9x/20 + 10 = xCorrect Option: D
Let the total journey be x km. then,
2x/15 + 9x/20 + 10 = x
⇒ 8x + 27x + 600 = 60x
⇒ x = 24
∴ Total journey = 24 km.
 Shard cover twothird of a certain distance at 4 km/hr and the remaining at 5 km/hr. If he takes 42 minutes in all, the distance is ?

 2.5 km.
 4.6 km.
 4 km.
 3 km.

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Let total distance be y km.
Then , (2y / 3) / 4 + ( y / 3) / 5 = 42/60Correct Option: D
Let total distance be y km.
Then , (2y / 3) / 4 + ( y / 3) / 5 = 42/60
⇒ y/6 + y/ 15 = 7/10
⇒ 5y + 2y = 21
∴ y = 3
∴ Required distance = 3 km.
 A boy goes to school with a speed of 3 km/hr. and return to the village with a speed of 2 km/hr. If he takes 5 hours in all, then distance between the village and the school is ?

 6 km.
 7 km.
 8 km.
 9 km.

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Let The required distance be y km.
Then, y/3 + y/2 = 5Correct Option: A
Let The required distance be y km.
Then, y/3 + y/2 = 5
⇒ 2y + 3y = 30
⇒ y = 6 km
 A distance is covered in 2 hours 45 min at 4 km/hr How much time will be taken to cover it at 16.5 km/hr ?

 40 min.
 41 min. 15 sec.
 45 min.
 90 min.

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Distance = (4 x 11/4 )km.
= 11 km.
∴ Req. Time = 11km / (33/2) km/hrCorrect Option: A
Distance = (4 x 11/4 )km.
= 11 km.
∴ Req. Time = 11km / (33/2) km/hr
= 2 x (11 / 33) hr.
=(2 / 3) x 60 minutes
= 40 minutes