Speed, Time and Distance


  1. Rahim covers a certain distance in 14 hrs 40 min. He covers one half of the distance by train at 60 km/hr. and rest half by road at 50 km/hr. The distance travelled by him is ?









  1. View Hint View Answer Discuss in Forum

    Let the total distance be y km.
    Then, (y/2) x (1/60) + (y/2) x (1/50) = 44/3

    Correct Option: D

    Let the total distance be y km.
    Then, (y/2) x (1/60) + (y/2) x (1/50) = 44/3
    ⇒ y/120 + y/100 = 44/3
    ⇒ 5y + 6y = 8800
    ⇒ y = 800
    ∴ Required distance = 800km.


  1. A man perform 2/15 of the total journey by rail, 9/20 by tonga and the remaining 10 km on foot. This total journey is ?









  1. View Hint View Answer Discuss in Forum

    Let the total journey be x km. then,
    2x/15 + 9x/20 + 10 = x

    Correct Option: D

    Let the total journey be x km. then,
    2x/15 + 9x/20 + 10 = x
    ⇒ 8x + 27x + 600 = 60x
    ⇒ x = 24
    ∴ Total journey = 24 km.



  1. Shard cover two-third of a certain distance at 4 km/hr and the remaining at 5 km/hr. If he takes 42 minutes in all, the distance is ?









  1. View Hint View Answer Discuss in Forum

    Let total distance be y km.
    Then , (2y / 3) / 4 + ( y / 3) / 5 = 42/60

    Correct Option: D

    Let total distance be y km.
    Then , (2y / 3) / 4 + ( y / 3) / 5 = 42/60
    ⇒ y/6 + y/ 15 = 7/10
    ⇒ 5y + 2y = 21
    ∴ y = 3
    ∴ Required distance = 3 km.


  1. A boy goes to school with a speed of 3 km/hr. and return to the village with a speed of 2 km/hr. If he takes 5 hours in all, then distance between the village and the school is ?









  1. View Hint View Answer Discuss in Forum

    Let The required distance be y km.
    Then, y/3 + y/2 = 5

    Correct Option: A

    Let The required distance be y km.
    Then, y/3 + y/2 = 5
    ⇒ 2y + 3y = 30
    ⇒ y = 6 km



  1. A distance is covered in 2 hours 45 min at 4 km/hr How much time will be taken to cover it at 16.5 km/hr ?









  1. View Hint View Answer Discuss in Forum

    Distance = (4 x 11/4 )km.
    = 11 km.
    ∴ Req. Time = 11km / (33/2) km/hr

    Correct Option: A

    Distance = (4 x 11/4 )km.
    = 11 km.
    ∴ Req. Time = 11km / (33/2) km/hr
    = 2 x (11 / 33) hr.
    =(2 / 3) x 60 minutes
    = 40 minutes