A and B travel the same distance at speed of 9 km/hr and

A and B travel the same distance at speed of 9 km/hr and 10 km/hr respectively. If A takes 36 minutes more than B, the distance travelled by each is

Let the distance between A and B be x km, then

x	−	x	=	36	=	3
9	−	10	=	60	=	5

⇒	x	=	3
	90		5

⇒ x =	3	× 90 = 54 km.
	5

Second Method :
Here, S₁ = 9, t₁ = x

S₂ = 10, t₂ = x −	36
	60

S₁t₁ = S₂t₂

9 × x = 10		x −	36
			60

9x = 10x – 6x = 6
Distance travelled
= 9 × 6 = 54 km