Speed, Time and Distance


  1. Walking at
    6
    th of his usual speed a man
    7
    is 25 minutes late. His usual time to cover this distance is
    1. 2 hours 30 minutes
    2. 2 hours 15 minutes
    3. 2 hours 25 minutes
    4. 2 hours 10 minutes

  1. View Hint View Answer Discuss in Forum

    Time and speed are inversely proportional.

    ∴ 
    7
    × Usual time – Usual time = 25 minutes
    6

    ⇒ 
    7
    − 1= 25 minutes
    6

    ⇒  Usual time ×
    1
    = 25 minutes
    6

    ∴  Usual time = 25 × 6
    = 150 minutes
    = 2 hours 30 minutes
    Second Method :
    Here, A = 6, B = 7,
    t =
    25
    =
    5
    hrs.
    6012

    Usual time =
    A
    × time
    Diff. of A and B

    =
    6
    ×
    5
    =
    5
    hrs.
    (7 − 6)122

    = 2 hours 30 minutes

    Correct Option: A

    Time and speed are inversely proportional.

    ∴ 
    7
    × Usual time – Usual time = 25 minutes
    6

    ⇒ 
    7
    − 1= 25 minutes
    6

    ⇒  Usual time ×
    1
    = 25 minutes
    6

    ∴  Usual time = 25 × 6
    = 150 minutes
    = 2 hours 30 minutes
    Second Method :
    Here, A = 6, B = 7,
    t =
    25
    =
    5
    hrs.
    6012

    Usual time =
    A
    × time
    Diff. of A and B

    =
    6
    ×
    5
    =
    5
    hrs.
    (7 − 6)122

    = 2 hours 30 minutes


  1. Walking at
    3
    of his usual speed,
    4
    a man is 1
    1
    hours late. His usual time to
    2
    cover the same distance, (in hours) is
    1. 4
      1
      2
    2. 4
    3. 5
      1
      2
    4. 5

  1. View Hint View Answer Discuss in Forum

    Time and speed are inversely proportional.

    ∴ 
    4
    of usual time –usual time
    3

    =
    3
    2

    ⇒ 
    1
    × usual time =
    3
    32

    ∴  Usual time =
    3 × 3
    =
    9
    22

    = 4
    1
    hours
    2

    Second Method :
    Here, A = 3, B = 4, t =
    3
    2

    Usual time =
    A
    × time
    Diff. of A and B

    =
    3
    ×
    3
    (4 − 3)2

    = 4
    1
    hrs.
    2

    Correct Option: A

    Time and speed are inversely proportional.

    ∴ 
    4
    of usual time –usual time
    3

    =
    3
    2

    ⇒ 
    1
    × usual time =
    3
    32

    ∴  Usual time =
    3 × 3
    =
    9
    22

    = 4
    1
    hours
    2

    Second Method :
    Here, A = 3, B = 4, t =
    3
    2

    Usual time =
    A
    × time
    Diff. of A and B

    =
    3
    ×
    3
    (4 − 3)2

    = 4
    1
    hrs.
    2



  1. By walking at
    3
    of his usual speed,
    4
    a man reaches his office 20 minutes later than his usual time. The usual time taken by him to reach his office is
    1. 75 minutes
    2. 60 minutes
    3. 40 minutes
    4. 30 minutes

  1. View Hint View Answer Discuss in Forum

    4
    of usual time = Usual time + 20 minutes
    3

    ∴ 
    1
    of usual time = 20 minutes
    3

    ⇒  Usual time = 20 × 3
    = 60 minutes
    Second Method :
    Here, A = 3, B= 4, t = 20 minutes
    Usual time taken =
    A
    × time
    Diff. of A and B

    =
    3
    × 20 = 60 minutes
    (4 − 3)

    Correct Option: B

    4
    of usual time = Usual time + 20 minutes
    3

    ∴ 
    1
    of usual time = 20 minutes
    3

    ⇒  Usual time = 20 × 3
    = 60 minutes
    Second Method :
    Here, A = 3, B= 4, t = 20 minutes
    Usual time taken =
    A
    × time
    Diff. of A and B

    =
    3
    × 20 = 60 minutes
    (4 − 3)


  1. Walking at three-fourth of his usual speed, a man covers a certain distance in 2 hours more than the time he takes to cover the distance at his usual speed. The time taken by him to cover the distance with his usual speed is
    1. 4.5 hours
    2. 5.5 hours
    3. 6 hours
    4. 5 hours

  1. View Hint View Answer Discuss in Forum

    4
    ×usual time – usual time = 2
    3

    ⇒ 
    1
    usual time = 2
    3

    ∴  Usual time = 2 × 3 = 6 hours
    Second Method :
    Here,
    A
    =
    3
    , time= 2 hrs.
    B4

    Usual time
    =
    A
    × time
    Diff. of A and B

    =
    3
    × 2 = 6 hours
    (4 − 3)

    Correct Option: C

    4
    ×usual time – usual time = 2
    3

    ⇒ 
    1
    usual time = 2
    3

    ∴  Usual time = 2 × 3 = 6 hours
    Second Method :
    Here,
    A
    =
    3
    , time= 2 hrs.
    B4

    Usual time
    =
    A
    × time
    Diff. of A and B

    =
    3
    × 2 = 6 hours
    (4 − 3)



  1. A car travelling with
    5
    of its usual speed covers
    7
    42 km in 1 hour 40 min 48 sec. What is the usual speed of the car?
    1. 17
      6
      km/hr
      7
    2. 35 km/hr
    3. 25 km/hr
    4. 30 km/hr

  1. View Hint View Answer Discuss in Forum

    1 hr 40 min 48 sec

    = 1 hr 40 +
    48
    min
    60

    = 1 hr 40 +
    4
    min
    5

    = 1 hr
    204
    min
    5

    = 1 +
    204
    hr
    300

    =
    504
    hr
    300

    ∴  Speed =
    42
    504
    300

    = 25 kmph
    Now,
    5
    ×usual speed = 25
    7

    ∴  Usual speed =
    25 × 7
    5

    = 35 kmph

    Correct Option: B

    1 hr 40 min 48 sec

    = 1 hr 40 +
    48
    min
    60

    = 1 hr 40 +
    4
    min
    5

    = 1 hr
    204
    min
    5

    = 1 +
    204
    hr
    300

    =
    504
    hr
    300

    ∴  Speed =
    42
    504
    300

    = 25 kmph
    Now,
    5
    ×usual speed = 25
    7

    ∴  Usual speed =
    25 × 7
    5

    = 35 kmph