Speed, Time and Distance
- How long does a train, 75 metre long, moving at 60 km/hr take to pass a certain telegraph post?
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Distance covered by train = Length of train
Speed of train = 60 kmph= 60 × 5 m./sec. 18 = 50 m./sec. 3 ∴ Required time = Distance Speed = 75 seconds (50/3) = 75 × 3 seconds 50
= 4.5 secondsCorrect Option: B
Distance covered by train = Length of train
Speed of train = 60 kmph= 60 × 5 m./sec. 18 = 50 m./sec. 3 ∴ Required time = Distance Speed = 75 seconds (50/3) = 75 × 3 seconds 50
= 4.5 seconds
- A train 240 metres in length crosses a telegraph post in 16 seconds. The speed of the train is
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When a train crosses a pole it travels a distance equal to its length.
∴ Speed of train = 240 = 15 m./sec. 16 = 15 × 18 kmph. 5
= 54 kmph.Correct Option: C
When a train crosses a pole it travels a distance equal to its length.
∴ Speed of train = 240 = 15 m./sec. 16 = 15 × 18 kmph. 5
= 54 kmph.
- In what time will a train, 60 metre long, running at the rate of 36 km/hr pass a telegraph post ?
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Speed of train = 36 kmph
= 36 × 5 m./sec. 18
= 10 m./sec.∴ Required time = Length of train Speed of train = 60 = 6 seconds 10 Correct Option: D
Speed of train = 36 kmph
= 36 × 5 m./sec. 18
= 10 m./sec.∴ Required time = Length of train Speed of train = 60 = 6 seconds 10
- A train 150m long passes a telegraphic post in 12 seconds. Find the speed of the train.(in km/hr)
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Distance covered by train in crossing a telegraphic post = length of train
∴ Speed of train = Distance Time = 150 m./sec. 12 = 150 × 18 kmph 12 5
= 45 kmphCorrect Option: D
Distance covered by train in crossing a telegraphic post = length of train
∴ Speed of train = Distance Time = 150 m./sec. 12 = 150 × 18 kmph 12 5
= 45 kmph
- In what time will a 100 metre long train running with a speed of 50 km/hr cross a pillar ?
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Speed of train = 50 kmph
= 50 × 5 m./sec. 18 = 125 m./sec. 9 ∴ Required time = (100/125) seconds 9 = 100 × 9 seconds 125
= 7.2 secondsCorrect Option: C
Speed of train = 50 kmph
= 50 × 5 m./sec. 18 = 125 m./sec. 9 ∴ Required time = (100/125) seconds 9 = 100 × 9 seconds 125
= 7.2 seconds