Speed, Time and Distance
- I walk a certain distance and ride back taking a total time of 37 minutes. I could walk both ways in 55 minutes. How long would it take me to ride both ways?
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Two ways walking time = 55 min ...(i)
One way walking + One way riding time = 37 min. ....(ii)
By 2 × (ii) – (i),
2 ways riding time
= 2×37–55 = 19 minutesCorrect Option: B
Two ways walking time = 55 min ...(i)
One way walking + One way riding time = 37 min. ....(ii)
By 2 × (ii) – (i),
2 ways riding time
= 2×37–55 = 19 minutes
- Rubi goes to a multiplex at the speed of 3 km/hr to see a movie and reaches 5 minutes late. If she travels at the speed of 4 km/hr she reaches 5 minutes early. Then the distance of the multiplex from her starting point is
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Distance between starting
point and multiplex = x metreTime = Distance Speed
According to the question,x − x = 5 + 5 ⇒ 4x − 3x = 1 3 4 60 12 6 ⇒ x = 1 ⇒ x = 12 = 2 km. 12 6 6 Correct Option: A
Distance between starting
point and multiplex = x metreTime = Distance Speed
According to the question,x − x = 5 + 5 ⇒ 4x − 3x = 1 3 4 60 12 6 ⇒ x = 1 ⇒ x = 12 = 2 km. 12 6 6
- A and B start running at the same time and from the same point around a circle. If A can complete one round in 40 seconds and B in 50 seconds, how many seconds will they take to reach the starting point simultaneously ?
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Required time = LCM of 40 and 50 seconds
= 200 secondsCorrect Option: B
Required time = LCM of 40 and 50 seconds
= 200 seconds
- Two persons ride towards each other from two places 55 km apart, one riding at 12km/hr and the other at 10 km/hr. In what time will they be 11 km apart?
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Relative speed
= 12 + 10 = 22 kmph
Distance covered
= 55 – 11 = 44 km∴ Required time = 44 hours 22
= 2 hoursCorrect Option: C
Relative speed
= 12 + 10 = 22 kmph
Distance covered
= 55 – 11 = 44 km∴ Required time = 44 hours 22
= 2 hours
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his office 20 minutes late. Then his usual time for walking to his office is :Walking at 3 of his usual speed, a man reaches 4
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Usual time = x minutes
New time = 4x minutes 3 ∵ Speed ∝ 1 Time
According to the question,4x − x = 20 3 ⇒ x = 20 3
⇒ x = 60 minutes i.e. 1 hour.Correct Option: A
Usual time = x minutes
New time = 4x minutes 3 ∵ Speed ∝ 1 Time
According to the question,4x − x = 20 3 ⇒ x = 20 3
⇒ x = 60 minutes i.e. 1 hour.