Speed, Time and Distance

Speed, Time and Distance

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Aptitude miscellaneous
  1. A train is moving with a speed of 92.4 km/hr. how many meters will it cover in 10 min. ?








  1. View Hint View Answer Discuss in Forum

    Speed in m/sec = ( 5 / 18 ) x Speed in kms/hr.
    92.4 kms/hr = 92.4 x (5 / 18) m/sec.
    ∴ Req. distance = 92.4 x ( 5 / 18 ) x 600 meters

    Correct Option: B

    Speed in m/sec = ( 5 / 18 ) x Speed in kms/hr.
    92.4 kms/hr = 92.4 x (5 / 18) m/sec.
    ∴ Req. distance = 92.4 x ( 5 / 18 ) x 600 meters
    = 15400 m.

  1. If a man takes 4 hours to cover a distance of 15 km. how much time will be needed to cover 63 km. at the same speed ?








  1. View Hint View Answer Discuss in Forum

    Required time = (4 / 15) x 63 hrs.

    Correct Option: B

    Required time = (4 / 15) x 63 hrs.
    = 16 hrs. 48 min

  1. A distance is covered in 2 hours 45 min at 4 km/hr How much time will be taken to cover it at 16.5 km/hr ?








  1. View Hint View Answer Discuss in Forum

    Distance = (4 x 11/4 )km.
    = 11 km.
    ∴ Req. Time = 11km / (33/2) km/hr

    Correct Option: A

    Distance = (4 x 11/4 )km.
    = 11 km.
    ∴ Req. Time = 11km / (33/2) km/hr
    = 2 x (11 / 33) hr.
    =(2 / 3) x 60 minutes
    = 40 minutes

  1. A boy goes to school with a speed of 3 km/hr. and return to the village with a speed of 2 km/hr. If he takes 5 hours in all, then distance between the village and the school is ?








  1. View Hint View Answer Discuss in Forum

    Let The required distance be y km.
    Then, y/3 + y/2 = 5

    Correct Option: A

    Let The required distance be y km.
    Then, y/3 + y/2 = 5
    ⇒ 2y + 3y = 30
    ⇒ y = 6 km

  1. Shard cover two-third of a certain distance at 4 km/hr and the remaining at 5 km/hr. If he takes 42 minutes in all, the distance is ?








  1. View Hint View Answer Discuss in Forum

    Let total distance be y km.
    Then , (2y / 3) / 4 + ( y / 3) / 5 = 42/60

    Correct Option: D

    Let total distance be y km.
    Then , (2y / 3) / 4 + ( y / 3) / 5 = 42/60
    ⇒ y/6 + y/ 15 = 7/10
    ⇒ 5y + 2y = 21
    ∴ y = 3
    ∴ Required distance = 3 km.