Speed, Time and Distance


  1. A train is running at 36 km/hr. If it crosses a pole in 25 seconds, its length is
    1. 248 m
    2. 250 m
    3. 255 m
    4. 260 m

  1. View Hint View Answer Discuss in Forum

    Speed of train = 36 kmph

    =
    36 × 5
    m/sec = 10 m/sec.
    18

    ∴  Length of train
    = Speed × time
    = 10 × 25 = 250 metre

    Correct Option: B

    Speed of train = 36 kmph

    =
    36 × 5
    m/sec = 10 m/sec.
    18

    ∴  Length of train
    = Speed × time
    = 10 × 25 = 250 metre


  1. A train, 240 m long crosses a man walking along the line in opposite direction at the rate of 3 kmph in 10 seconds. The speed of the train is
    1. 63 kmph
    2. 75 kmph
    3. 83.4 kmph
    4. 86.4 kmph

  1. View Hint View Answer Discuss in Forum

    If the speed of train be x kmph then,
    Its relative speed = (x + 3) kmph

    ∴  Time =
    Length of the train
    Relative Speed

    ⇒ 
    10
    3600

    240
    = 1000
    x + 3

    =
    240
    1000(x + 3)

    ⇒  x + 3 = 86.4
    ⇒  x = 83.4 kmph

    Correct Option: C

    If the speed of train be x kmph then,
    Its relative speed = (x + 3) kmph

    ∴  Time =
    Length of the train
    Relative Speed

    ⇒ 
    10
    3600

    240
    = 1000
    x + 3

    =
    240
    1000(x + 3)

    ⇒  x + 3 = 86.4
    ⇒  x = 83.4 kmph



  1. A train, 300m long, passed a man, walking along the line in the same direction at the rate of 3 km/hr in 33 seconds. The speed of the train is
    1. 30 km/h
    2. 32 km/h
    3. 32
      8
      km/h
      11
    4. 35
      8
      km/h
      11

  1. View Hint View Answer Discuss in Forum

    If the speed of the train be x kmph, then relative speed = (x – 3) kmph.

    or (x – 3) ×
    5
    m/sec
    18

    ∴ 
    300
    = 33
    (x − 3) ×
    5
    18

    ⇒  5400 = 33 × 5 (x – 3)
    ⇒  360 = 11 (x – 3)
    ⇒  11x – 33 = 360
    ⇒  x =
    393
    = 35
    8
    kmph
    1111

    Correct Option: D

    If the speed of the train be x kmph, then relative speed = (x – 3) kmph.

    or (x – 3) ×
    5
    m/sec
    18

    ∴ 
    300
    = 33
    (x − 3) ×
    5
    18

    ⇒  5400 = 33 × 5 (x – 3)
    ⇒  360 = 11 (x – 3)
    ⇒  11x – 33 = 360
    ⇒  x =
    393
    = 35
    8
    kmph
    1111


  1. Buses start from a bus terminal with a speed of 20 km/hr at intervals of 10 minutes. What is the speed of a man coming from the opposite direction towards the bus terminal if he meets the buses at intervals of 8 minutes?
    1. 3 km/hr
    2. 4 km/hr
    3. 5 km/hr
    4. 7 km/hr

  1. View Hint View Answer Discuss in Forum

    Distance covered in 10 minutes at 20kmph = distance covered in 8 minutes at (20 + x )
    kmph

    ⇒  20 ×
    10
    =
    8
    (20 + x )
    6060

    ⇒  200 = 160 + 8x
    ⇒  8x = 40
    ⇒  x =
    40
    = 5 kmph
    8

    Correct Option: C

    Distance covered in 10 minutes at 20kmph = distance covered in 8 minutes at (20 + x )
    kmph

    ⇒  20 ×
    10
    =
    8
    (20 + x )
    6060

    ⇒  200 = 160 + 8x
    ⇒  8x = 40
    ⇒  x =
    40
    = 5 kmph
    8



  1. A passenger train 150m long is travelling with a speed of 36 km/ hr. If a man is cycling in the direction of train at 9 km/hr., the time taken by the train to pass the man is
    1. 10 sec
    2. 15 sec
    3. 18 sec
    4. 20 sec

  1. View Hint View Answer Discuss in Forum

    Relative speed of train
    = (36 – 9) kmph = 27 kmph

    =
    27 × 5
    m/sec
    18

    =
    15
    m/sec
    2

    ∴  Required time =
    Length of the train
    Relative speed

    =
    150 × 2
    = 20 seconds
    15

    Correct Option: D

    Relative speed of train
    = (36 – 9) kmph = 27 kmph

    =
    27 × 5
    m/sec
    18

    =
    15
    m/sec
    2

    ∴  Required time =
    Length of the train
    Relative speed

    =
    150 × 2
    = 20 seconds
    15