Speed, Time and Distance


  1. A train is running at 36 km/hr. If it crosses a pole in 25 seconds, its length is









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    Speed of train = 36 kmph

    =
    36 × 5
    m/sec = 10 m/sec.
    18

    ∴  Length of train
    = Speed × time
    = 10 × 25 = 250 metre

    Correct Option: B

    Speed of train = 36 kmph

    =
    36 × 5
    m/sec = 10 m/sec.
    18

    ∴  Length of train
    = Speed × time
    = 10 × 25 = 250 metre


  1. A train, 240 m long crosses a man walking along the line in opposite direction at the rate of 3 kmph in 10 seconds. The speed of the train is









  1. View Hint View Answer Discuss in Forum

    If the speed of train be x kmph then,
    Its relative speed = (x + 3) kmph

    ∴  Time =
    Length of the train
    Relative Speed

    ⇒ 
    10
    3600

    240
    = 1000
    x + 3

    =
    240
    1000(x + 3)

    ⇒  x + 3 = 86.4
    ⇒  x = 83.4 kmph

    Correct Option: C

    If the speed of train be x kmph then,
    Its relative speed = (x + 3) kmph

    ∴  Time =
    Length of the train
    Relative Speed

    ⇒ 
    10
    3600

    240
    = 1000
    x + 3

    =
    240
    1000(x + 3)

    ⇒  x + 3 = 86.4
    ⇒  x = 83.4 kmph



  1. A train, 300m long, passed a man, walking along the line in the same direction at the rate of 3 km/hr in 33 seconds. The speed of the train is









  1. View Hint View Answer Discuss in Forum

    If the speed of the train be x kmph, then relative speed = (x – 3) kmph.

    or (x – 3) ×
    5
    m/sec
    18

    ∴ 
    300
    = 33
    (x − 3) ×
    5
    18

    ⇒  5400 = 33 × 5 (x – 3)
    ⇒  360 = 11 (x – 3)
    ⇒  11x – 33 = 360
    ⇒  x =
    393
    = 35
    8
    kmph
    1111

    Correct Option: D

    If the speed of the train be x kmph, then relative speed = (x – 3) kmph.

    or (x – 3) ×
    5
    m/sec
    18

    ∴ 
    300
    = 33
    (x − 3) ×
    5
    18

    ⇒  5400 = 33 × 5 (x – 3)
    ⇒  360 = 11 (x – 3)
    ⇒  11x – 33 = 360
    ⇒  x =
    393
    = 35
    8
    kmph
    1111


  1. Buses start from a bus terminal with a speed of 20 km/hr at intervals of 10 minutes. What is the speed of a man coming from the opposite direction towards the bus terminal if he meets the buses at intervals of 8 minutes?









  1. View Hint View Answer Discuss in Forum

    Distance covered in 10 minutes at 20kmph = distance covered in 8 minutes at (20 + x )
    kmph

    ⇒  20 ×
    10
    =
    8
    (20 + x )
    6060

    ⇒  200 = 160 + 8x
    ⇒  8x = 40
    ⇒  x =
    40
    = 5 kmph
    8

    Correct Option: C

    Distance covered in 10 minutes at 20kmph = distance covered in 8 minutes at (20 + x )
    kmph

    ⇒  20 ×
    10
    =
    8
    (20 + x )
    6060

    ⇒  200 = 160 + 8x
    ⇒  8x = 40
    ⇒  x =
    40
    = 5 kmph
    8



  1. A passenger train 150m long is travelling with a speed of 36 km/ hr. If a man is cycling in the direction of train at 9 km/hr., the time taken by the train to pass the man is









  1. View Hint View Answer Discuss in Forum

    Relative speed of train
    = (36 – 9) kmph = 27 kmph

    =
    27 × 5
    m/sec
    18

    =
    15
    m/sec
    2

    ∴  Required time =
    Length of the train
    Relative speed

    =
    150 × 2
    = 20 seconds
    15

    Correct Option: D

    Relative speed of train
    = (36 – 9) kmph = 27 kmph

    =
    27 × 5
    m/sec
    18

    =
    15
    m/sec
    2

    ∴  Required time =
    Length of the train
    Relative speed

    =
    150 × 2
    = 20 seconds
    15