Speed, Time and Distance
- A and B started at the same time from the same place for a certain destination.
1 hour 15 minutes after A. B reached the destination inB walking at 5 of A’s speed reached the destination 6
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1 − 5 
of time taken by B 6
=1 hour 15 minutes
∴ Time taken by B
= 1 hour 15 minutes × 6
=7 hours 30 minutesCorrect Option: C
1 − 5 of time taken by B 6
=1 hour 15 minutes
∴ Time taken by B
= 1 hour 15 minutes × 6
=7 hours 30 minutes
- In covering a distance of 30 km, Abhay takes 2 hours more than Sameer. If Abhay doubles his speed, then he would take 1 hour less than Sameer. Abhay's speed (in km/hr) is
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Abhay’s speed = x kmph
Sameer’s speed = y kmph∴ 30 − 30 = 2 ...(i) x y and, 30 − 30 = 1 ...(ii) y 2x
On adding,30 − 30 = 3 x 2x ⇒ 60 − 30 = 3 2x ⇒ 30 = 3 ⇒ 6x = 30 2x
⇒ x = 5 kmphCorrect Option: A
Abhay’s speed = x kmph
Sameer’s speed = y kmph∴ 30 − 30 = 2 ...(i) x y and, 30 − 30 = 1 ...(ii) y 2x
On adding,30 − 30 = 3 x 2x ⇒ 60 − 30 = 3 2x ⇒ 30 = 3 ⇒ 6x = 30 2x
⇒ x = 5 kmph
- A man takes 6 hours 15 minutes in walking a distance and riding back to the starting place. He could walk both ways in 7 hours 45 minutes. The time taken by him to ride both ways, is
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Time taken in walking both ways = 7 hours 45 minutes ....(i)
Time taken in walking one way and riding back = 6 hours 15 minutes ....(ii)
By equation (ii) × 2 – (i), we have Time taken by the man to ride both ways
= 12 hours 30 minutes – 7 hours 45 minutes
= 4 hours 45 minutesCorrect Option: C
Time taken in walking both ways = 7 hours 45 minutes ....(i)
Time taken in walking one way and riding back = 6 hours 15 minutes ....(ii)
By equation (ii) × 2 – (i), we have Time taken by the man to ride both ways
= 12 hours 30 minutes – 7 hours 45 minutes
= 4 hours 45 minutes
- A man completed a certain journey by a car. If he covered 30% of the distance at the speed of 20km/hr, 60% of the distance at 40km/hr and the remaining distance at 10km/hr; his average speed for the whole journey was
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Let the total distance be 100 km.
Average speed = Total distance covered Time taken = 100 3 + 3 + 1 2 2 = 100 3 + 3 + 2 2 = 100 × 2 = 25 kmph 8 Correct Option: A
Let the total distance be 100 km.
Average speed = Total distance covered Time taken = 100 3 + 3 + 1 2 2 = 100 3 + 3 + 2 2 = 100 × 2 = 25 kmph 8
- From two places, 60 km apart, A and B start towards each other at the same time and meet each other after 6 hours.
and B travelled with double of his speed, they would have met after 5 hours. The speed of A isHad A travelled with 2 of his speed 3
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Let the speed of A = x kmph and that of B = y kmph
According to the question,
x × 6 + y × 6 = 60
⇒ x + y = 10 ....(i)and, 2 x × 5 + 2y × 5 = 60 3
⇒ 10x + 30y = 180
⇒ x + 3y = 18 ...(ii)
From equations (i) × (3) – (ii)
3x + 3y – x – 3y = 30 – 18
⇒ 12x = 12
⇒ x = 6 kmph.Correct Option: B
Let the speed of A = x kmph and that of B = y kmph
According to the question,
x × 6 + y × 6 = 60
⇒ x + y = 10 ....(i)and, 2 x × 5 + 2y × 5 = 60 3
⇒ 10x + 30y = 180
⇒ x + 3y = 18 ...(ii)
From equations (i) × (3) – (ii)
3x + 3y – x – 3y = 30 – 18
⇒ 12x = 12
⇒ x = 6 kmph.
