Speed, Time and Distance
- In what time will a train 100 metres long cross an electric pole, if its speed be 144 km/hour ?
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Speed of the train
= 144 kmph = 144 × 5 = 40 m/s 18
When a train crosses a pole, it covers a distance equal to its own length.The required time = 100 40 = 5 = 2 5. seconds. 2 Correct Option: A
Speed of the train
= 144 kmph = 144 × 5 = 40 m/s 18
When a train crosses a pole, it covers a distance equal to its own length.The required time = 100 40 = 5 = 2 5. seconds. 2
- A man observed that a train 120 m long crossed him in 9 seconds. The speed (in km/hr) of the train was
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Speed of train
= 120 × 18 = 48 kmph 9 5 Correct Option: C
Speed of train
= 120 × 18 = 48 kmph 9 5
- A passenger train 150m long is travelling with a speed of 36 km/ hr. If a man is cycling in the direction of train at 9 km/hr., the time taken by the train to pass the man is
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Relative speed of train
= (36 – 9) kmph = 27 kmph= 27 × 5 m/sec 18 = 15 m/sec 2 ∴ Required time = Length of the train Relative speed = 150 × 2 = 20 seconds 15 Correct Option: D
Relative speed of train
= (36 – 9) kmph = 27 kmph= 27 × 5 m/sec 18 = 15 m/sec 2 ∴ Required time = Length of the train Relative speed = 150 × 2 = 20 seconds 15
- Buses start from a bus terminal with a speed of 20 km/hr at intervals of 10 minutes. What is the speed of a man coming from the opposite direction towards the bus terminal if he meets the buses at intervals of 8 minutes?
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Distance covered in 10 minutes at 20kmph = distance covered in 8 minutes at (20 + x )
kmph⇒ 20 × 10 = 8 (20 + x ) 60 60
⇒ 200 = 160 + 8x
⇒ 8x = 40⇒ x = 40 = 5 kmph 8 Correct Option: C
Distance covered in 10 minutes at 20kmph = distance covered in 8 minutes at (20 + x )
kmph⇒ 20 × 10 = 8 (20 + x ) 60 60
⇒ 200 = 160 + 8x
⇒ 8x = 40⇒ x = 40 = 5 kmph 8
- A train, 300m long, passed a man, walking along the line in the same direction at the rate of 3 km/hr in 33 seconds. The speed of the train is
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If the speed of the train be x kmph, then relative speed = (x – 3) kmph.
or (x – 3) × 5 m/sec 18 ∴ 300 = 33 (x − 3) × 5 18
⇒ 5400 = 33 × 5 (x – 3)
⇒ 360 = 11 (x – 3)
⇒ 11x – 33 = 360⇒ x = 393 = 35 8 kmph 11 11 Correct Option: D
If the speed of the train be x kmph, then relative speed = (x – 3) kmph.
or (x – 3) × 5 m/sec 18 ∴ 300 = 33 (x − 3) × 5 18
⇒ 5400 = 33 × 5 (x – 3)
⇒ 360 = 11 (x – 3)
⇒ 11x – 33 = 360⇒ x = 393 = 35 8 kmph 11 11