Speed, Time and Distance

Speed, Time and Distance

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Aptitude miscellaneous
  1. A train covers a distance in 1 h 40 min, if it runs at a speed of 96 km/h on an average. Find the speed at which the train must run reduce the time of journey to 1 h 20 min.








  1. View Hint View Answer Discuss in Forum

    Distance= Speed x Time = 96 x (100/60) = 160 km
    New time = 80/60 h = 4/3 h

    Correct Option: A

    Distance= Speed x Time = 96 x (100/60) = 160 km
    New time = 80/60 h = 4/3 h
    New speed = 160 x 3/4 = 40 x 3 =120 km/h

  1. A person goes from one point to another point with a speed of 5 km/h and comes back to starting point with a speed of 3 km/h. Find the average speed for the whole journey.?








  1. View Hint View Answer Discuss in Forum

    Average speed = 2AB/(A + B)
    = 2 x 5 x 3/(5 + 3)

    Correct Option: D

    Average speed = 2AB/(A + B)
    = 2 x 5 x 3/(5 + 3)
    = 30/8
    = 3.75 km/h

  1. John started from A to B and Vinod from B to A. If the distance betweeen A and B is 125 km and they meet at 75 km from A, what is the ratio of John's speed to that of Vinod's speed?








  1. View Hint View Answer Discuss in Forum

    John's speed : Vinod's speed = 75 : ( 125 - 75 )

    Correct Option: B

    John's speed : Vinod's speed = 75 : ( 125 - 75 )
    = 75 : 50 = 3 : 2

  1. Moving 6/7 of its usual speed a train is 10 min late. Find its usual time to cover the journey.








  1. View Hint View Answer Discuss in Forum

    New speed = 6/7 of usual speed
    Now, time taken = 7/6 of usual time
    (7/6 of the usual time) - (usual time) = 10 min

    Correct Option: D

    New speed = 6/7 of usual speed
    Now, time taken = 7/6 of usual time
    (7/6 of the usual time) - (usual time) = 10 min
    ⇒ 1/6 of the usual time = 10 min
    ∴ Usual time = 60 min

  1. A certain distance is covered at a certain speed. If half of the distance is covered in double time, the ratio of the two speeds is .








  1. View Hint View Answer Discuss in Forum

    Let L km distance be covered in T h. So, speed in first case = L/T km/h.
    And speed in second case = (L/2)/2T = L/4T km/h

    Correct Option: A

    Let L km distance be covered in T h. So, speed in first case = L/T km/h.
    And speed in second case = (L/2)/2T = L/4T km/h
    ∴ Required ratio = L/T : L/4T =1 : 1/4 = 4 : 1