Speed, Time and Distance

A man travels 3 th of the distance 4
and 2 km on foot. The total distance travelled by the man is :of his journey by bus, 1 th by rickshaw 6

 12 km
 18 km
 20 km
 24 km

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Part of journey covered by bus and rickshaw
= 3 + 1 = 9 + 2 = 11 4 6 12 12
Distance covered on foot= 1 − 11 = 1 part 12 12
∴ Total journey
= 12 × 2 = 24 km.Correct Option: D
Part of journey covered by bus and rickshaw
= 3 + 1 = 9 + 2 = 11 4 6 12 12
Distance covered on foot= 1 − 11 = 1 part 12 12
∴ Total journey
= 12 × 2 = 24 km.
 A train is running at a speed of 116 km/hr. The distance covered by the train in metres in 18 seconds is :

 900 metre
 1160 metre
 508 metre
 580 metre

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Speed of train = 116 kmph
= 116 × 5 m/sec. 18 = 580 m./sec. 18
∴ Required distance
= Speed × Time= 580 × 18 metre 18
= 580 metreCorrect Option: D
Speed of train = 116 kmph
= 116 × 5 m/sec. 18 = 580 m./sec. 18
∴ Required distance
= Speed × Time= 580 × 18 metre 18
= 580 metre
 Two buses travel to a place at 45 km./hr. and 60 km./hr. respectively.
less than the first for the journey, the length of the journey is :If the second bus takes 5 1 hours 2

 900 km.
 945 km.
 990 km.
 1350 km.

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Time taken by bus moving at 60 kmph = t hours
Distance = Speed × Time∴ 60 × t = 45 × t + 11 2 ⇒ 60t – 45t = 45 × 11 2 ⇒ 15t = 45 × 11 2 ⇒ t = 45 × 11 = 33 15 × 2 2 = 60 × 33 = 990 km. 2 Correct Option: C
Time taken by bus moving at 60 kmph = t hours
Distance = Speed × Time∴ 60 × t = 45 × t + 11 2 ⇒ 60t – 45t = 45 × 11 2 ⇒ 15t = 45 × 11 2 ⇒ t = 45 × 11 = 33 15 × 2 2 = 60 × 33 = 990 km. 2
 A bus travels at the speed of 36 km/hr, then the distance covered by it in one second is

 10 metre
 15 metre
 12.5 metre
 13.5 metre

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Speed of bus = 36 kmph.
= 36 × 5 m/sec. = 10 m/sec. 18
∴ Distance covered in 1 second = 10 metreCorrect Option: A
Speed of bus = 36 kmph.
= 36 × 5 m/sec. = 10 m/sec. 18
∴ Distance covered in 1 second = 10 metre
 A man cycles at the speed of 8 km/hr and reaches office at 11 am and when he cycles at the speed of 12 km/hr he reaches office at 9 am. At what speed should he cycle so that he reaches his office at 10 am?

 9.6 kmph.
 10 kmph.
 11.2 kmph.
 Cannot be determined

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Distance of the office = x km.
Difference of time = 2 hours∴ x − x = 2 8 12 ⇒ 3x − 2x = 2 24 ⇒ x = 2 ⇒ x = 48 km. 24
∴ Time taken at the speed of 8 kmph= 48 = 6 hours 8
∴ Required time to reach the
office at 10 a.m. i.e., in 5 hours= 48 kmph 5
= 9.6 kmphCorrect Option: A
Distance of the office = x km.
Difference of time = 2 hours∴ x − x = 2 8 12 ⇒ 3x − 2x = 2 24 ⇒ x = 2 ⇒ x = 48 km. 24
∴ Time taken at the speed of 8 kmph= 48 = 6 hours 8
∴ Required time to reach the
office at 10 a.m. i.e., in 5 hours= 48 kmph 5
= 9.6 kmph