## Speed, Time and Distance

#### Speed, Time and Distance

1. A train 50 metres long passes a platform of length 100 metres in 10 seconds. The speed of the train in metre/second is
1. 50
2. 10
3. 15
4. 20

1.  Speed of train = Length of (train + platform) Time taken to crossing

 = (50 + 100) 10

 = 150 = 15 m/sec 10

##### Correct Option: C

 Speed of train = Length of (train + platform) Time taken to crossing

 = (50 + 100) 10

 = 150 = 15 m/sec 10

1. A train 270 metres long is running at a speed of 36 km per hour, then it will cross a bridge of
length 180 metres in :
1. 40 sec
2. 45 sec
3. 50 sec
4. 35 sec

1.  36 kmph = 36 × 5 m/sec. 18

= 10 m/sec.
 Required time = 270 + 180 10

= 45 seconds

##### Correct Option: B

 36 kmph = 36 × 5 m/sec. 18

= 10 m/sec.
 Required time = 270 + 180 10

= 45 seconds

1. A train 200 m long running at 36 kmph takes 55 seconds to cross a bridge. The length of the bridge is
1. 375 m.
2. 300 m.
3. 350 m.
4. 325 m.

1. Speed of train = 36kmph

 = 36 × 5 = 10 m/sec. 18

If the length of bridge be x metre, then
 10 = 200 + x 55

⇒  200 + x = 550
⇒  x = 550 – 200 = 350 metre.

Second Method :
Here, x = 200 m
 u = 36 km/hr, 36 × 5 m/second = 10 m/sec 18

y = ?, t = 55 sec
using
 t = x + y u

 55 = 200 + y 10

y = 550 – 200
y = 350 m

##### Correct Option: C

Speed of train = 36kmph

 = 36 × 5 = 10 m/sec. 18

If the length of bridge be x metre, then
 10 = 200 + x 55

⇒  200 + x = 550
⇒  x = 550 – 200 = 350 metre.

Second Method :
Here, x = 200 m
 u = 36 km/hr, 36 × 5 m/second = 10 m/sec 18

y = ?, t = 55 sec
using
 t = x + y u

 55 = 200 + y 10

y = 550 – 200
y = 350 m

1. A train of length 500 feet crosses a platform of length 700 feet in 10 seconds. The speed of the train is
1. 70 ft/second
2. 85 ft/second
3. 100 ft/second
4. 120 ft/second

1.  Speed of train = Length of (train + platform) Time taken to cross

 = 500 + 700 feet/second = 120 feet/second 10

Second Method :
Here, x = 500 feet, y = 700 feet
t = 10 seconds, u = ?
using
 t = x + y u

 u = 500 + 700 10

= 120ft/second

##### Correct Option: D

 Speed of train = Length of (train + platform) Time taken to cross

 = 500 + 700 feet/second = 120 feet/second 10

Second Method :
Here, x = 500 feet, y = 700 feet
t = 10 seconds, u = ?
using
 t = x + y u

 u = 500 + 700 10

= 120ft/second

1. A train, 110m long , is running at a speed of 60km/hr. How many seconds does it take to
cross another train, 170 m long, standing on parallel track ?
1. 15.6 sec
2. 16.8 sec
3. 17.2 sec
4. 18 sec

1.  Speed of train = Sum of length of both trains Time taken

 ⇒ 60 × 5 = 110 + 170 = 280 18 t t

 ⇒ t = 280 × 18 = 16.8 seconds. 60 × 5

##### Correct Option: B

 Speed of train = Sum of length of both trains Time taken

 ⇒ 60 × 5 = 110 + 170 = 280 18 t t

 ⇒ t = 280 × 18 = 16.8 seconds. 60 × 5