Speed, Time and Distance


  1. A train 50 metres long passes a platform of length 100 metres in 10 seconds. The speed of the train in metre/second is
    1. 50
    2. 10
    3. 15
    4. 20

  1. View Hint View Answer Discuss in Forum

    Speed of train =
    Length of (train + platform)
    Time taken to crossing

    =
    (50 + 100)
    10

    =
    150
    = 15 m/sec
    10

    Correct Option: C

    Speed of train =
    Length of (train + platform)
    Time taken to crossing

    =
    (50 + 100)
    10

    =
    150
    = 15 m/sec
    10


  1. A train 270 metres long is running at a speed of 36 km per hour, then it will cross a bridge of
    length 180 metres in :
    1. 40 sec
    2. 45 sec
    3. 50 sec
    4. 35 sec

  1. View Hint View Answer Discuss in Forum

    36 kmph =36 ×
    5
    m/sec.
    18

    = 10 m/sec.
    Required time =
    270 + 180
    10

    = 45 seconds

    Correct Option: B

    36 kmph =36 ×
    5
    m/sec.
    18

    = 10 m/sec.
    Required time =
    270 + 180
    10

    = 45 seconds



  1. A train 200 m long running at 36 kmph takes 55 seconds to cross a bridge. The length of the bridge is
    1. 375 m.
    2. 300 m.
    3. 350 m.
    4. 325 m.

  1. View Hint View Answer Discuss in Forum

    Speed of train = 36kmph

    = 36 ×
    5
    = 10 m/sec.
    18

    If the length of bridge be x metre, then
    10 =
    200 + x
    55

    ⇒  200 + x = 550
    ⇒  x = 550 – 200 = 350 metre.

    Second Method :
    Here, x = 200 m
    u = 36 km/hr,
    36 × 5
    m/second = 10 m/sec
    18

    y = ?, t = 55 sec
    using
    t =
    x + y
    u

    55 =
    200 + y
    10

    y = 550 – 200
    y = 350 m

    Correct Option: C

    Speed of train = 36kmph

    = 36 ×
    5
    = 10 m/sec.
    18

    If the length of bridge be x metre, then
    10 =
    200 + x
    55

    ⇒  200 + x = 550
    ⇒  x = 550 – 200 = 350 metre.

    Second Method :
    Here, x = 200 m
    u = 36 km/hr,
    36 × 5
    m/second = 10 m/sec
    18

    y = ?, t = 55 sec
    using
    t =
    x + y
    u

    55 =
    200 + y
    10

    y = 550 – 200
    y = 350 m


  1. A train of length 500 feet crosses a platform of length 700 feet in 10 seconds. The speed of the train is
    1. 70 ft/second
    2. 85 ft/second
    3. 100 ft/second
    4. 120 ft/second

  1. View Hint View Answer Discuss in Forum

    Speed of train =
    Length of (train + platform)
    Time taken to cross

    =
    500 + 700
    feet/second = 120 feet/second
    10

    Second Method :
    Here, x = 500 feet, y = 700 feet
    t = 10 seconds, u = ?
    using
    t =
    x + y
    u

    u =
    500 + 700
    10

    = 120ft/second

    Correct Option: D

    Speed of train =
    Length of (train + platform)
    Time taken to cross

    =
    500 + 700
    feet/second = 120 feet/second
    10

    Second Method :
    Here, x = 500 feet, y = 700 feet
    t = 10 seconds, u = ?
    using
    t =
    x + y
    u

    u =
    500 + 700
    10

    = 120ft/second



  1. A train, 110m long , is running at a speed of 60km/hr. How many seconds does it take to
    cross another train, 170 m long, standing on parallel track ?
    1. 15.6 sec
    2. 16.8 sec
    3. 17.2 sec
    4. 18 sec

  1. View Hint View Answer Discuss in Forum

    Speed of train =
    Sum of length of both trains
    Time taken

    ⇒ 
    60 × 5
    =
    110 + 170
    =
    280
    18t t

    ⇒ t =
    280 × 18
    = 16.8 seconds.
    60 × 5

    Correct Option: B

    Speed of train =
    Sum of length of both trains
    Time taken

    ⇒ 
    60 × 5
    =
    110 + 170
    =
    280
    18t t

    ⇒ t =
    280 × 18
    = 16.8 seconds.
    60 × 5