Speed, Time and Distance
 A train 50 metres long passes a platform of length 100 metres in 10 seconds. The speed of the train in metre/second is

 50
 10
 15
 20

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Speed of train = Length of (train + platform) Time taken to crossing = (50 + 100) 10 = 150 = 15 m/sec 10 Correct Option: C
Speed of train = Length of (train + platform) Time taken to crossing = (50 + 100) 10 = 150 = 15 m/sec 10
 A train 270 metres long is running at a speed of 36 km per hour, then it will cross a bridge of
length 180 metres in :

 40 sec
 45 sec
 50 sec
 35 sec

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36 kmph = 36 × 5 m/sec. 18
= 10 m/sec.Required time = 270 + 180 10
= 45 secondsCorrect Option: B
36 kmph = 36 × 5 m/sec. 18
= 10 m/sec.Required time = 270 + 180 10
= 45 seconds
 A train 200 m long running at 36 kmph takes 55 seconds to cross a bridge. The length of the bridge is

 375 m.
 300 m.
 350 m.
 325 m.

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Speed of train = 36kmph
= 36 × 5 = 10 m/sec. 18
If the length of bridge be x metre, then10 = 200 + x 55
⇒ 200 + x = 550
⇒ x = 550 – 200 = 350 metre.
Second Method :
Here, x = 200 mu = 36 km/hr, 36 × 5 m/second = 10 m/sec 18
y = ?, t = 55 sec
usingt = x + y u 55 = 200 + y 10
y = 550 – 200
y = 350 mCorrect Option: C
Speed of train = 36kmph
= 36 × 5 = 10 m/sec. 18
If the length of bridge be x metre, then10 = 200 + x 55
⇒ 200 + x = 550
⇒ x = 550 – 200 = 350 metre.
Second Method :
Here, x = 200 mu = 36 km/hr, 36 × 5 m/second = 10 m/sec 18
y = ?, t = 55 sec
usingt = x + y u 55 = 200 + y 10
y = 550 – 200
y = 350 m
 A train of length 500 feet crosses a platform of length 700 feet in 10 seconds. The speed of the train is

 70 ft/second
 85 ft/second
 100 ft/second
 120 ft/second

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Speed of train = Length of (train + platform) Time taken to cross = 500 + 700 feet/second = 120 feet/second 10
Second Method :
Here, x = 500 feet, y = 700 feet
t = 10 seconds, u = ?
usingt = x + y u u = 500 + 700 10
= 120ft/secondCorrect Option: D
Speed of train = Length of (train + platform) Time taken to cross = 500 + 700 feet/second = 120 feet/second 10
Second Method :
Here, x = 500 feet, y = 700 feet
t = 10 seconds, u = ?
usingt = x + y u u = 500 + 700 10
= 120ft/second
 A train, 110m long , is running at a speed of 60km/hr. How many seconds does it take to
cross another train, 170 m long, standing on parallel track ?

 15.6 sec
 16.8 sec
 17.2 sec
 18 sec

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Speed of train = Sum of length of both trains Time taken ⇒ 60 × 5 = 110 + 170 = 280 18 t t ⇒ t = 280 × 18 = 16.8 seconds. 60 × 5 Correct Option: B
Speed of train = Sum of length of both trains Time taken ⇒ 60 × 5 = 110 + 170 = 280 18 t t ⇒ t = 280 × 18 = 16.8 seconds. 60 × 5