Home » Aptitude » Speed, Time and Distance » Question
  1. A train after travelling 100 kms from P meets with an accident and then proceeds
    at
    3
    th of its original speed and arrives
    4
    at the terminus Q 90 minutes late. Had the accident occurred 60 kms further on, it would have reached 15 minutes sooner. Find the original speed of the train and the distance PQ.
    1. 65 kmph; 480 km
    2. 75 kmph; 450 km
    3. 80 kmph; 460 km
    4. 85 kmph; 460 km
Correct Option: C


Let P be the starting point, Q the terminus, M and N the places where accidents occur.
At (3/4)th of the original speed, the train will take 4/3 of its usual time to cover the same distance i.e., (1/3)rd more than the usual time.
(1/3)rd of the usual time to travel a distance of 60 kms between MN = 15 min.
∴  Usual time to travel 60 kms

= 15 × 3 = 45 min. =
3
hr.
4

∴  Usual speed of the train per hour
= 60 ×
4
= 80 km per hr.
3

Usual time taken to travel MQ = 90 × 3
= 270 min. or
9
hrs.
2

= 80 ×
9
= 360 km.
2

Therefore, the total distance PQ
= PM + MQ
= 100 + 360 = 460 kms.



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