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A train met with an accident 3 hours after starting, which detains it for one hour, after which it proceeds at 75% of its original speed. It arrives at the destination 4 hours late. Had the accident taken place 150 km further along the railway line,
Find the length of the trip and the original speed of the train.the train would have arrived only 3 1 hours late. 2
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- 1100 km ; 100 kmph
- 1200 km ; 100 kmph
- 1200 km ; 90 kmph
- 1600 km ; 90 kmph
Correct Option: B
Let A be the starting point, B the terminus. C and D are points where accidents take place.
∴ 0.75 = | |
4 |
By travelling a 3/4 of its original speed, the train would take 4/3 of its usual time i.e., 1/3 more of the usual time.
∴ 1/3 of the usual time taken to travel the distance CB.
= 4 – 1 = 3 hrs. ...(i)
and 1/3 of the usual time taken to travel the distance
DB = 3 | − 1 = 2 | hrs. ...(ii) | ||
2 | 2 |
Subtracting equation (ii) from (i)
we can write,
1/3 of the usual time taken to travel the distance
CD = 3 − 2 | = | hr. | ||
2 | 2 |
∴ Usual time taken to travel
CD (150 km) = | |||
2 | |||
3 |
= | hr. | |
2 |
Usual speed of the train
= | = 9 hrs. | |||||||||
3 |
Total time = 3 + 9 = 12 hrs.
∴ Length of the trip = 12 × 100 = 1200 km.