Compound Interest
- The principal amount which yields a compound interest of ₹ 208 in the second year at 4% is
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Let the principal be ₹ P.
Amount after first year = (P x 104)/100 and
amount after second year P x (104/100) x (4/100)
According to the question.
(P x 104 x 4)/(100 x 100) = 208Correct Option: A
Let the principal be ₹ P.
Amount after first year = (P x 104)/100 and
amount after second year P x (104/100) x (4/100)
According to the question.
(P x 104 x 4)/(100 x 100) = 208
∴ P = ₹ 5000
- The simple interest on a certain sum for 2 yr is ₹ 120 and compound interest is ₹ 129. Find the rate of interest.
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Here, n = 2 yr, SI = ₹ 120 and CI = ₹ 129
CI = SI (1+ R/200)
⇒ 129 = 120(1 + R/200)Correct Option: B
Here, n = 2 yr, SI = ₹ 120 and CI = ₹ 129
CI = SI (1+ R/200)
⇒ 129 = 120(1 + R/200)
⇒ 129/120 = 1 + R/200
⇒ (129/120) - 1 = R / 200
⇒ 9/120 = R/200
∴ R = (9 x 200)/120 = 15%
- The height of a tree increases every year 1/8 times. If the present height of the tree is 64 cm, then what will be its height after 2 yr?
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Percentage growth = (1/8) x 100 % = 12.5%
Height after 2 yr = 64 x (1+ 12.5/100)2Correct Option: C
Percentage growth = (1/8) x 100 % = 12.5%
Height after 2 yr = 64 x (1+ 12.5/100)2
= 64 x (9/8) x (9/8) = 81 cm
- An amount at the rate of 5% pa becomes ₹ 10 more at compound interest than that of simple interest after 2 yr. Calculate the principal.
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Here, CI - SI = 10, R = 5%, n = 2 yr and P = ?
According to the formula,
CI - SI = PR2/1002
⇒ 10 = (P x 25)/10000Correct Option: A
Here, CI - SI = 10, R = 5%, n = 2 yr and P = ?
According to the formula,
CI - SI = PR2/1002
⇒ 10 = (P x 25)/10000
∴ P = (400 x 10) = ₹ 4000
- A certain sum at compound interest amounts to ₹ 12960 in 2 yr and ₹ 13176 in 3 yr. Find the rate per cent per annum.
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SI for on ₹ 12960 for 1 yr
= 13176 - 12960 = ₹ 216
By formula, SI = (P x R x T)/ 100
⇒ 216 = (12960 x R x 1)/100Correct Option: C
SI for on ₹ 12960 for 1 yr
= 13176 - 12960 = ₹ 216
By formula, SI = (P x R x T)/ 100
⇒ 216 = (12960 x R x 1)/100
∴ R = 5/3 = 12/3