Compound Interest
- At what rate of compound interest per annum will a sum of Rs. 1200 become Rs. 1348.32 in 2 years?
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Here , Amount ( A ) = ₹ 1348.32 , P = ₹ 1200 , Rate ( R ) = ? , Time = 2 years
A = P 1 + R T 100 ⇒ 1348.32 = 1200 1 + R 2 100 ⇒ 1348.32 = 1 + R 2 1200 100 ⇒ 134832 = 1 + R 2 120000 100 ⇒ 11236 = 1 + R 2 10000 100 ⇒ 106 2 = 1 + R 2 100 100 ⇒ 106 = 1 + R 100 100
Correct Option: D
Here , Amount ( A ) = ₹ 1348.32 , P = ₹ 1200 , Rate ( R ) = ? , Time = 2 years
A = P 1 + R T 100 ⇒ 1348.32 = 1200 1 + R 2 100 ⇒ 1348.32 = 1 + R 2 1200 100 ⇒ 134832 = 1 + R 2 120000 100 ⇒ 11236 = 1 + R 2 10000 100 ⇒ 106 2 = 1 + R 2 100 100 ⇒ 106 = 1 + R 100 100 ⇒ 1 + 6 = 1 + R 100 100
⇒ R = 6% per annum.
- In how many years will ₹ 2,000 amounts to 2,420 at 10% per annum compound interest?
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Given that , P = ₹ 2,000 , A = ₹ 2420 , r = 10%, n = t years
Using the given formula ,A = P 1 + r n 100 2420 = 2000 1 + 10 t 100 2420 = 11 t 2000 10 ⇒ 11 t = 121 10 100
Correct Option: C
Given that , P = ₹ 2,000 , A = ₹ 2420 , r = 10%, n = t years
Using the given formula ,A = P 1 + r n 100 2420 = 2000 1 + 10 t 100 2420 = 11 t 2000 10 ⇒ 11 t = 121 10 100 ⇒ 11 t = 11 2 10 10
∴ t = 2 years
- The difference between simple interest and compound interest on Rs. 600 for 1 years at 10% per annum,reckoned half yearly is ?
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S.I. = Rs. (600 x 5 x 2)/100 = Rs.60
C.I.= Rs. [600 x (1 + 5/100)2 - 600] = Rs. 61.50Correct Option: D
S.I. = Rs. (600 x 5 x 2)/100 = Rs.60
C.I.= Rs. [600 x (1 + 5/100)2 - 600] = Rs. 61.50
∴ Requred Difference = Rs. (61.50 - 60) = Rs.1.50
- The simple interest on a certain sum for 2 years at 10% per annum is Rs.90. The corresponding compound interest is?
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Principle = (100 x interest) / (time x rate)
⇒ Sum = (100 x 90) / (2 x 10) = Rs. 450Correct Option: C
Principle = (100 x interest) / (time x rate)
⇒ Sum = (100 x 90) / (2 x 10) = Rs. 450
C.I. =Rs.[ 450 x (1 + 10/100)2 - 450] = Rs. 94.50
- What is the principle amount which earns Rs. 132 as compound interest for the second years at 10% per annum ?
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Let P the principle at the end of first year.
Then (P x 10 x 1)/100 =132
⇒ P =1320
Let Q be the original principle
Then, Q + (Q x 10 x 1)/100 =1320
⇒ Q =1200Correct Option: B
Let P the principle at the end of first year.
Then (P x 10 x 1)/100 =132
⇒ P =1320
Let Q be the original principle
Then, Q + (Q x 10 x 1)/100 =1320
⇒ Q =1200