Here, CI - SI = 10, R = 5%, n = 2 yr and P = ?
According to the formula,
CI - SI = PR²/100²
⇒ 10 = (P x 25)/10000

Correct Option: A

Here, CI - SI = 10, R = 5%, n = 2 yr and P = ?
According to the formula,
CI - SI = PR²/100²
⇒ 10 = (P x 25)/10000
∴ P = (400 x 10) = ₹ 4000

Let the principal be ₹ P.
Amount after first year = (P x 104)/100 and
amount after second year P x (104/100) x (4/100)
According to the question.
(P x 104 x 4)/(100 x 100) = 208

Correct Option: A

Let the principal be ₹ P.
Amount after first year = (P x 104)/100 and
amount after second year P x (104/100) x (4/100)
According to the question.
(P x 104 x 4)/(100 x 100) = 208
∴ P = ₹ 5000

Given, P = ₹ 9375, R₁ = 2% and R₂ = 4%
According to the formula,
A = P (1 + R₁/100) (1 + R₂/100)
= 9375 (1 + 2/100) (1 + 4/100)

Correct Option: A

Given, P = ₹ 9375, R₁ = 2% and R₂ = 4%
According to the formula,
A = P (1 + R₁/100) (1 + R₂/100)
= 9375 (1 + 2/100) (1 + 4/100)
= 9375 x (51/50) x (26/25)
= 7.5 x 51 x 26
= ₹ 9945

Now CI = A - P = 9945 - 9375 = ₹ 570

Given, P = 10 crore
and population after 3 yr = 13.31 crore
According to the formula,
Population after n yr = P (1 + R/100 )ⁿ

Correct Option: C

Given, P = 10 crore
and population after 3 yr = 13.31 crore
According to the formula,
Population after n yr = P (1 + R/100 )ⁿ
⇒ 13.31 = 10 (1 + R/100 )³
⇒ 1331/1000 = (1 + R/100 )³
⇒ (11/10)³ = (1 + R/100 )³
⇒ 1 + R/100 = 11/10
⇒ R/100 = 11/10 - 1 = 1/10
∴ R = 10%

Given that , Difference = C.I. - S.I. = ₹ 48 , Time = 2 years , Rate = 20%
Using the given formula ,

Difference of two years = P		r2
		10000

Correct Option: B

Given that , Difference = C.I. - S.I. = ₹ 48 , Time = 2 years , Rate = 20%
Using the given formula ,

Difference of two years = P		r2
		10000

⇒ 48 = P		400
		10000