Compound Interest

Compound Interest

Easy Questions
Moderate Questions
Difficult Questions
Compound Interest Tutorial

Aptitude

Simplification
Number System
Fractions
Elementary Algebra
LCM and HCF
Approximation
Unitary Method
Linear Equation
Quadratic Equation
Discount
Average
Surds and Indices
Percentage
Square root and cube root
Order of Magnitude
Work and Wages
Odd Man Out and Series
Algebra
Profit and Loss
Stocks and Shares
True Discount
Ratio, Proportion
Partnership
Alligation or Mixture
Time and Work
Pipes and Cistern
Speed, Time and Distance
Problem on Trains
Height and Distance
Banker's Discount
Boats and Streams
Races and games
Problems on Ages
Clocks and Calendars
Simple interest
Compound Interest
Sets and Functions
Area and Perimeter
Volume and Surface Area of Solid Figures
Sequences and Series
Plane Geometry
Logarithm
Probability
Permutation and Combination
Statistics
Mensuration
Trigonometry
Aptitude miscellaneous
  1. A sum of Rs. 12000 deposited at compound interest becomes doubles after 5 years. After 20 years it will become ?








  1. View Hint View Answer Discuss in Forum

    ∵ 2P = P(1 +r/100)5
    ⇒ (1 +r/100)5 = 2
    ∴ (1 + r/100)20 = 24 = 16

    Correct Option: B

    ∵ 2P = P(1 +r/100)5
    ⇒ (1 +r/100)5 = 2
    ∴ (1 + r/100)20 = 24 = 16
    Thus, P(1 +r/100)20 = 16P
    = Rs. (12000 x 16)
    = Rs. 192000

  1. A loan was repaid in two annual instalment of ₹ 1089 each. If the rate of interest be 10% per annum compounded annually, the sum borrowed was ?








  1. View Hint View Answer Discuss in Forum

    Principle = ₹ 1089
    ∴ P/{(1 + 10/100) + (1 + 10/100)2 } = 1089

    Correct Option: B

    Principle = ₹ 1089
    ∴ P/{(1 + 10/100) + (1 + 10/100)2 } = 1089
    ⇒ P = {(1089 x 10/11) + (1089 x 100/121)} = (990 + 900) = ₹ 1890

  1. Vandana invested an amount of ₹ 8000 in a fixed deposit scheme for 2 yr at the rate of 5% pa compound interest. How much amount will Vandana get on maturity of the fixed deposit?








  1. View Hint View Answer Discuss in Forum

    Given, P = ₹ 8000, R = 5% and n = 2 Yr
    According to the formula,
    Amount = p ( 1 + R / 100 )n
    = 8000 ( 1 + 5/100 )2

    Correct Option: D

    Given, P = ₹ 8000, R = 5% and n = 2 Yr
    According to the formula,
    Amount = p ( 1 + R / 100 )n
    = 8000 ( 1 + 5/100 )2
    = 8000 x (105/100)2
    =8000 x (21/20) x (21/20)
    = 20 x 21 x 21
    = ₹ 8820

  1. Raja invested ₹ 15000 at the rate of 10 % pa for 1 yr. If the interest is compound half-yearly, then find the amount received by Raja at the end of the year.








  1. View Hint View Answer Discuss in Forum

    Given P = ₹ 15000 , R = 10 %
    and n = 1 yr
    Accounting to the formula,
    Amount = P(1 + R/(2 x 100))2n
    = 15000 x (1 + 5/100 )2

    Correct Option: A

    Given P = ₹ 15000 , R = 10 %
    and n = 1 yr
    Accounting to the formula,
    Amount = P(1 + R/(2 x 100))2n
    = 15000 x (1 + 5/100 )2
    = 15000 x (105/100 )2
    = 15000 x (21/20) x (21/20)
    = ₹ 16537.50

  1. What amount will be received on a sum of ₹ 15000 in 11/4 yr at 12% pa, if interest is compounded quarterly?








  1. View Hint View Answer Discuss in Forum

    Given, P = ₹ 15000, R = 12 %
    and n = 11/4 = 5/4 Yr
    According to the formula,
    Amount = p [1 + R/(100 x 4)]4n
    = 15000 x [1 + 12/(100 x 4)]4 x 5/4

    Correct Option: D

    Given, P = ₹ 15000, R = 12 %
    and n = 11/4 = 5/4 Yr
    According to the formula,
    Amount = p [1 + R/(100 x 4)]4n
    = 15000 x [1 + 12/(100 x 4)]4 x 5/4
    = 15000(412/400)5
    = 15000 (103/100)5
    = 15000 x (103/100) x (103/100) x (103/100) x (103/100) x (103/100)
    = (15 x 103 x 103 x 103 x 103 x 103) / 10000000
    = ₹ 17389.111
    = ₹ 17389.12 (approx )