Compound Interest


  1. If the difference between simple and compound interest on some principal amount at 20% per annum for three years is ₹ 48, then the principal amount is:









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    Given that , Difference ( D ) = ₹ 48 , r = 20%
    Using the given formula ,

    For three years , P =
    D × 1003
    r2(r + 300)

    Correct Option: B

    Given that , Difference ( D ) = ₹ 48 , r = 20%
    Using the given formula ,

    For three years , P =
    D × 1003
    r2(r + 300)

    P =
    48 × 1003
    = Rs. 375
    400(20 + 300)


  1. At what rate per annum will ₹ 32000 yield a compound interest of ₹ 5044 in 9 months interest being compounded quarterly ?









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    Here , Compound interest ( CI ) = ₹ 5044 ,Principal ( P ) = ₹ 32000 , Time = 9 months = ( 9 / 12 ) year = ( 3 / 4 ) years
    Let the rate of CI be R percent per annum.

    ∴  CI = P 1 +
    R
    T − 1
    100

    ∵  Interest is compounded quarterly
    ⇒  5044 = 32000 1 +
    R
    3 − 1
    400

    ⇒ 
    5044
    = 1 +
    R
    3 − 1
    32000 400

    ⇒  1 +
    R
    3 − 1 =
    1261
    400 8000

    ⇒  1 +
    R
    3 = 1 +
    1261
    400 8000

    ⇒  1 +
    R
    3 =
    9261
    =
    21
    3
    400 800020

    Correct Option: A

    Here , Compound interest ( CI ) = ₹ 5044 ,Principal ( P ) = ₹ 32000 , Time = 9 months = ( 9 / 12 ) year = ( 3 / 4 ) years
    Let the rate of CI be R percent per annum.

    ∴  CI = P 1 +
    R
    T − 1
    100

    ∵  Interest is compounded quarterly
    ⇒  5044 = 32000 1 +
    R
    3 − 1
    400

    ⇒ 
    5044
    = 1 +
    R
    3 − 1
    32000 400

    ⇒  1 +
    R
    3 − 1 =
    1261
    400 8000

    ⇒  1 +
    R
    3 = 1 +
    1261
    400 8000

    ⇒  1 +
    R
    3 =
    9261
    =
    21
    3
    400 800020

    ⇒  1 +
    R
    =
    21
    R
    =
    21
    − 1 =
    1
    400204002020

    ⇒  R =
    400
    = 20 % per annum
    20



  1. B borrows ₹ 5,000 from A at 6% p.a. simple interest and lends it to C at compound interest of 10% p.a. If B collects the money back from C after 2 years and repays A, the profit made by B in the transaction is









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    Given that , Principal = ₹ 5,000 , Time = 2 years , Rate = 6% p.a

    Interest got by A =
    Principal × Time × Rate
    100

    Interest got by A =
    5000 × 2 × 6
    = Rs. 600
    100

    Now , Time = 2 years , Rate = 10% p.a
    C.I. received by B = P 1 +
    R
    T − 1
    100

    C.I. received by B = 5000 1 +
    10
    2 − 1
    100

    C.I. received by B = 5000
    11
    2 − 1
    10

    Correct Option: C

    Given that , Principal = ₹ 5,000 , Time = 2 years , Rate = 6% p.a

    Interest got by A =
    Principal × Time × Rate
    100

    Interest got by A =
    5000 × 2 × 6
    = Rs. 600
    100

    Now , Time = 2 years , Rate = 10% p.a
    C.I. received by B = P 1 +
    R
    T − 1
    100

    C.I. received by B = 5000 1 +
    10
    2 − 1
    100

    C.I. received by B = 5000
    11
    2 − 1
    10

    C.I. received by B = 5000
    121
    − 1
    100

    C.I. received by B =
    5000 × 21
    = Rs. 1050
    100

    B’s profit = C.I. received by B - Interest got by A
    ∴  B’s profit = Rs. (1050 – 600) = Rs. 450


  1. Rs. 260200 is divided between Ram and Shyam so that the amount that Ram receives in 4 years is the same as that Shyam receives in 6 years. If the interest is compounded annually at the rate of 4% per annum then Ram’s share is









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    Let Ram’s share be Rs. y.
    ∴  Shyam’s share = Rs. (260200 – y)

    A = P1 +
    R
    T
    100

    According to question ,
    ⇒ y1 +
    R
    4= (260200 – y)1 +
    R
    6
    100100

    ⇒  y = (260200 – y)1 +
    4
    2
    100

    ⇒  y = (260200 – y)1 +
    1
    2
    25

    ⇒  y = (260200 – y)
    26
    2
    25

    ⇒  y = (260200 – y)
    676
    625

    ⇒ 
    625y
    + y = 260200
    676

    ⇒ 
    625y + 676y
    = 260200
    676

    Correct Option: B

    Let Ram’s share be Rs. y.
    ∴  Shyam’s share = Rs. (260200 – y)

    A = P1 +
    R
    T
    100

    According to question ,
    ⇒ y1 +
    R
    4 = (260200 – y)1 +
    R
    6
    100100

    ⇒  y = (260200 – y)1 +
    4
    2
    100

    ⇒  y = (260200 – y)1 +
    1
    2
    25

    ⇒  y = (260200 – y)
    26
    2
    25

    ⇒  y = (260200 – y)
    676
    625

    ⇒ 
    625y
    + y = 260200
    676

    ⇒ 
    625y + 676y
    = 260200
    676

    ⇒ 
    1301y
    = 260200
    676

    ⇒  y =
    260200 × 676
    = Rs. 135200
    1301



  1. A man borrowed some money and agreed to pay-off by paying Rs. 3150 at the end of the 1st year and Rs. 4410 at the end of the 2nd year. If the rate of compound interest is 5% per annum, then the sum is









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    As per the given in question , y1 = Rs. 3150 , y2 = Rs. 4410 , R = 5%

    P =
    y1
    +
    y2
    1 +
    R
    1 +
    R
    2
    1010


    Correct Option: C

    As per the given in question , y1 = Rs. 3150 , y2 = Rs. 4410 , R = 5%

    P =
    x1
    +
    x2
    1 +
    R
    1 +
    R
    2
    1010


    P = Rs.
    3150 × 20
    +
    4410 × 400
    21441

    P = Rs. (3000 + 4000)
    P = Rs. 7000