Mensuration


  1. A cone of height 7 cm and base radius 1 cm is carved from a cuboidal block of wood 10 cm × 5cm × 2 cm. [Assuming π = 22/7] The percentage wood wasted in the process is :









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    Volume of cone =
    1
    πr²h =
    1
    ×
    22
    × 1 × 7 =
    22
    cu.cm.
    3373

    Volume of cubical block = 10 × 5 × 2 cm³. = 100 cm³.
    Wastage of wood = 100 -
    22
    cm³ =
    300 - 22
    =
    278
    cm³
    333

    ´
    ∴ % Wastage =
    278
    × 100
    3
    100

    =
    278
    = 92
    2
    %
    33

    Correct Option: A

    Volume of cone =
    1
    πr²h =
    1
    ×
    22
    × 1 × 7 =
    22
    cu.cm.
    3373

    Volume of cubical block = 10 × 5 × 2 cm³. = 100 cm³.
    Wastage of wood = 100 -
    22
    cm³ =
    300 - 22
    =
    278
    cm³
    333

    ´
    ∴ % Wastage =
    278
    × 100
    3
    100

    =
    278
    = 92
    2
    %
    33


  1. If the radius of a cylinder is decreased by 50% and the height is increased by 50% to form a new cylinder, the volume will be decreased by









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    Required percentage decrease = 100 -
    50 × 50 × 150
    = 100 - 37.5 = 62.5 %
    100 × 100

    Correct Option: C

    Required percentage decrease = 100 -
    50 × 50 × 150
    = 100 - 37.5 = 62.5 %
    100 × 100



  1. Each of the height and base-radius of a cone is increased by 100%. The percentage increase in the volume of the cone is









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    Required per cent

    200 × 200 × 200
    - 100 = 800 - 100 = 700 %
    100 × 100

    Correct Option: A

    Required per cent

    200 × 200 × 200
    - 100 = 800 - 100 = 700 %
    100 × 100


  1. If both the radius and height of a right circular cone are increased by 20%, its volume will be increased by









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    Let height and radius both of a cylinder change by x%, then volume changes by

    3x +
    3x²
    +
    % = 3 × 20 +
    3 × 20 × 20
    +
    20 × 20 × 20
    %
    100100²10010000

    = (60 + 12 + 0.8)% = 72.8%

    Correct Option: D

    Let height and radius both of a cylinder change by x%, then volume changes by

    3x +
    3x²
    +
    % = 3 × 20 +
    3 × 20 × 20
    +
    20 × 20 × 20
    %
    100100²10010000

    = (60 + 12 + 0.8)% = 72.8%



  1. If the height of a right circular cone is increased by 200% and the radius of the base is reduced by 50%, the volume of the









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    Volume of original cone =
    1
    πr²h
    3

    Now, r1 = radius of new cone = r/2
    h1 = height of new cone = 3h
    ∴ V1 =
    1
    πr1²h1 =
    1
    π
    × 3h =
    1
    πr²h ×
    3
    =
    3
    V
    334344

    ∴ Decrease % = V -
    3
    V × 100
    4
    V

    = 25%

    Correct Option: D

    Volume of original cone =
    1
    πr²h
    3

    Now, r1 = radius of new cone = r/2
    h1 = height of new cone = 3h
    ∴ V1 =
    1
    πr1²h1 =
    1
    π
    × 3h =
    1
    πr²h ×
    3
    =
    3
    V
    334344

    ∴ Decrease % = V -
    3
    V × 100
    4
    V

    = 25%