Mensuration
- How many cubes, each of edge 3 cm, can be cut from a cube of edge 15 cm?
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No. of Cubes = Volume of larger cube Volume of smaller cube = (15)³ = 15 × 15 × 15 = 5 × 5 × 5 = 125 (3)³ 3 × 3 × 3 Correct Option: C
No. of Cubes = Volume of larger cube Volume of smaller cube = (15)³ = 15 × 15 × 15 = 5 × 5 × 5 = 125 (3)³ 3 × 3 × 3
- A right cylindrical vessel is full with water. How many right cones having the same diameter and height as that of the right cylinder will be needed to store that water ? (Take π = 22/7)
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Volume of cylindrical vessel = πr²h
Volume of cone = 1 πr²h 3 ∴ Number of cones = πr²h = 3 1 πr²h 3 Correct Option: C
Volume of cylindrical vessel = πr²h
Volume of cone = 1 πr²h 3 ∴ Number of cones = πr²h = 3 1 πr²h 3
- Marbles of diameter 1.4 cm are dropped into a cylindrical beaker containing some water and are fully submerged. The dia meter of the beaker is 7 cm. Find how many marbles have been dropped in it if the water rises by 5.6 cm ?
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Volume of raised water in cylindrical beaker
= πr²h = 22 × 7 × 7 × 5.6 7 2 2
= 215.6 cu.cm.Volume of a marble = 4 πr³ 3 = 4 × 22 × (0.7)³ = 4.312 cu.cm. 3 7 3 ∴ Number of marbles = 215.6 = 215.6 × 3 = 150 4.312 4.312 3 Correct Option: B
Volume of raised water in cylindrical beaker
= πr²h = 22 × 7 × 7 × 5.6 7 2 2
= 215.6 cu.cm.Volume of a marble = 4 πr³ 3 = 4 × 22 × (0.7)³ = 4.312 cu.cm. 3 7 3 ∴ Number of marbles = 215.6 = 215.6 × 3 = 150 4.312 4.312 3
- The diameter of the base of a cylindrical drum is 35 dm. and the height is 24 dm. It is full of kerosene. How many tins each of size 25 cm × 22 cm × 35 cm can be filled with kerosene from the drum? (Use π = 22/7)
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Required number of tins = Volume of cylindricaldrum volume of a tin = 22 × 350 × 350 × 240 = 1200 7 × 2 × 2 × 25 × 22 × 35 Correct Option: A
Required number of tins = Volume of cylindricaldrum volume of a tin = 22 × 350 × 350 × 240 = 1200 7 × 2 × 2 × 25 × 22 × 35
- The circumference of the base of a circular cylinder is 6π cm. The height of the cylinder is equal to the diameter of the base. How many litres of water can it hold?
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Let Circumference of base = πd
⇒ πd = 6π ⇒ d = 6 cm
∴ Height, h = 6 cm
Volume of the cylinder,V = πr²h = πd³ = π(6)³ cc = 54π cc 4 4 4 Correct Option: A
Let Circumference of base = πd
⇒ πd = 6π ⇒ d = 6 cm
∴ Height, h = 6 cm
Volume of the cylinder,V = πr²h = πd³ = π(6)³ cc = 54π cc 4 4 4