Mensuration


  1. If O is the centroid and AD, BE and CF are the three medians of ∆ABC with an area of 96 cm² then the area of ∆BOD in cm² is









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    Point O is the centroid of ∆ABC.
    ∴ ∆AOB ≡ ∆AOC ≡ ∆BOC
    Again, ∆BOD ≡ ∆COD

    ∴ Area of ∆BOD =
    1
    × Area of ∆ABC
    6

    =
    1
    × 96 = 16 sq.cm.
    6

    Correct Option: C


    Point O is the centroid of ∆ABC.
    ∴ ∆AOB ≡ ∆AOC ≡ ∆BOC
    Again, ∆BOD ≡ ∆COD

    ∴ Area of ∆BOD =
    1
    × Area of ∆ABC
    6

    =
    1
    × 96 = 16 sq.cm.
    6


  1. In a triangle ABC, AB = 8 cm, AC = 10 cm and ÐB = 90°, then the area of ∆ABC is









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    AC = 10 cm.
    AB = 8 cm.
    ∴ BC = √AC² - AB²
    = √10² - 8² = √100 - 64
    = √36 = 6 cm.

    ∴ Area of ∆ABC =
    1
    × AB × BC
    2

    ∴ Area of ∆ABC =
    1
    × 8 × 6 = 24 sq. cm.
    2

    Correct Option: D


    AC = 10 cm.
    AB = 8 cm.
    ∴ BC = √AC² - AB²
    = √10² - 8² = √100 - 64
    = √36 = 6 cm.

    ∴ Area of ∆ABC =
    1
    × AB × BC
    2

    ∴ Area of ∆ABC =
    1
    × 8 × 6 = 24 sq. cm.
    2



  1. In figure, DE || BC. If DE = 3 cm, BC = 6 cm and area of ∆ADE = 15 sq. cm, then the area of ∆ABC is










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    DE || BC
    ∴ ∠ADE = ∠ABC
    ∠AED = ∠ACB
    By AA–similarity,
    ∆ADE ~ ∆ABC

    Area of ∆ABC
    =
    BC²
    Area of ∆ADEDE²

    Area of ∆ABC
    =
    15

    =
    36
    = 4
    9

    ∴ Area of DABC = 4 × 15
    = 60 sq. cm.

    Correct Option: D


    DE || BC
    ∴ ∠ADE = ∠ABC
    ∠AED = ∠ACB
    By AA–similarity,
    ∆ADE ~ ∆ABC

    Area of ∆ABC
    =
    BC²
    Area of ∆ADEDE²

    Area of ∆ABC
    =
    15

    =
    36
    = 4
    9

    ∴ Area of DABC = 4 × 15
    = 60 sq. cm.


  1. ∆ABC is a right angled triangle, the radius of its circumcircle is 3 cm and the length of its altitude drawn from the opposite vertex to the hypotenuse is 2 cm. Then the area of the triangle is









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    The angle in a semi–circle is a right angle.
    ∴ BC = 2 × 3 = 6 cm.
    OA = 2 cm.

    ∴ Area of ∆ABC =
    1
    × BC × OA
    2

    =
    1
    × 6 × 2 = 6 sq.cm.
    2

    Correct Option: C


    The angle in a semi–circle is a right angle.
    ∴ BC = 2 × 3 = 6 cm.
    OA = 2 cm.

    ∴ Area of ∆ABC =
    1
    × BC × OA
    2

    =
    1
    × 6 × 2 = 6 sq.cm.
    2



  1. The lengths of the diagonals of a rhombus are 8 cm and 6 cm. The area of rhombus is :









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    Area of the rhombus

    ∴ Area of ∆ABC =
    1
    × d1 × d2
    2

    =
    1
    × 8 × 6 sq. cm. = 24 sq.cm.
    2

    Correct Option: D

    Area of the rhombus

    ∴ Area of ∆ABC =
    1
    × d1 × d2
    2

    =
    1
    × 8 × 6 sq. cm. = 24 sq.cm.
    2