Mensuration


  1. If the volume of two right circular cones are in the ratio 4 : 1 and their diameter are in the ratio 5 : 4, then the ratio of their height is :









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    V1
    =
    r1²h1
    V2r2²h2

    4
    =
    25
    ×
    h1
    116h2

    h1
    =
    16 × 4
    =
    64
    or 64 : 25
    h22525

    Correct Option: C

    V1
    =
    r1²h1
    V2r2²h2

    4
    =
    25
    ×
    h1
    116h2

    h1
    =
    16 × 4
    =
    64
    or 64 : 25
    h22525


  1. The volume of a conical tent is 1232 cu. m and the area of its base is 154 sq. m. Find the length of the canvas required to build the tent, if the canvas is 2m in width. (Take π = (22/7)









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    πr² = 154

    22
    × r² = 154
    7

    ⇒ r² =
    154 × 722
    ⇒ r = 7 metre
    22

    1
    πr²h = 1232
    3

    h
    =
    1232
    = 8
    3154

    ⇒ h = 24 metre
    Area of canvas curved surface area of cone = πrl
    = πr √h² + r²
    =
    22
    × 7 = √24² + 4²sq. metre
    7

    = 22 × 25 = 550 sq. metre
    ∴ Its length =
    550
    = 275 metre
    2

    Correct Option: D

    πr² = 154

    22
    × r² = 154
    7

    ⇒ r² =
    154 × 722
    ⇒ r = 7 metre
    22

    1
    πr²h = 1232
    3

    h
    =
    1232
    = 8
    3154

    ⇒ h = 24 metre
    Area of canvas curved surface area of cone = πrl
    = πr √h² + r²
    =
    22
    × 7 = √24² + 4²sq. metre
    7

    = 22 × 25 = 550 sq. metre
    ∴ Its length =
    550
    = 275 metre
    2



  1. What is the volume of a cube (in cubic cm) whose diagonal measures 4√3 cm?









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    Diagonal of a cube = √3 × side
    ⇒ 4√3 = √3 × side
    ∴ Side = 4 cm
    ∴ Volume of the cube = (side)³ = (4)³ = 64 cm³

    Correct Option: C

    Diagonal of a cube = √3 × side
    ⇒ 4√3 = √3 × side
    ∴ Side = 4 cm
    ∴ Volume of the cube = (side)³ = (4)³ = 64 cm³


  1. From a solid cylinder of height 10 cm and radius of the base 6 cm, a cone of same height and same base is removed. The volume of the remaining solid is :









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    Volume of the remaining solid

    πr²h -
    1
    π r² h
    3

    =
    2
    πr²h =
    2
    π × 6 × 6 × 10 = 240π cu.cm.
    33

    Correct Option: A

    Volume of the remaining solid

    πr²h -
    1
    π r² h
    3

    =
    2
    πr²h =
    2
    π × 6 × 6 × 10 = 240π cu.cm.
    33



  1. From a solid cylinder whose height is 12 cm and diameter 10cm, a conical cavity of same height and same diameter of the base is hollowed out. The volume of the remaining solid is approx imately (π = 22/7)









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    Volume of solid cylinder = πr²h

    Volume of cone =
    1
    π r² h
    3

    Difference = π r²h –
    1
    π r² h
    3

    =
    2
    π²h =
    2
    ×
    22
    × 5 × 5 × 12 = 628.57 cu.cm.
    337

    Correct Option: C

    Volume of solid cylinder = πr²h

    Volume of cone =
    1
    π r² h
    3

    Difference = π r²h –
    1
    π r² h
    3

    =
    2
    π²h =
    2
    ×
    22
    × 5 × 5 × 12 = 628.57 cu.cm.
    337