Mensuration


  1. The radius of a cylinder is 10 cm and height is 4 cm. The number of centimetres that may be added either to the radius or to the height to get the same increase in the volume of the cylinder is









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    Let radius be increased byx cm. then Volume of cylinder = π(10 + x)² × 4
    Again, let height be increased by x cm.
    then Volume of cylinder = π × 10² (4 + x)
    ∴ π (10 + x)² × 4 = π (10)² (4 + x)
    ⇒ π(10 + x)² = 25 (4 + x)
    ⇒ 100 + 20x + x² = 100 + 25x
    ⇒ x² – 5x = 0
    ⇒ x (x – 5) = 0
    ⇒ x = 5 cm

    Correct Option: A

    Let radius be increased byx cm. then Volume of cylinder = π(10 + x)² × 4
    Again, let height be increased by x cm.
    then Volume of cylinder = π × 10² (4 + x)
    ∴ π (10 + x)² × 4 = π (10)² (4 + x)
    ⇒ π(10 + x)² = 25 (4 + x)
    ⇒ 100 + 20x + x² = 100 + 25x
    ⇒ x² – 5x = 0
    ⇒ x (x – 5) = 0
    ⇒ x = 5 cm


  1. The radii of the base of a cylinder and a cone are in the ratio √3 : √2 and their heights are in the ratio √2 : √3 . Their volumes are in the ratio of









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    Volume of cylinder
    =
    πr1²h1
    Volume of cone
    1
    πr2²h2
    3

    = 3.
    r1
    ²
    h1
    r2h2

    = 3 ×
    3
    ² ×
    2
    23

    = 3 ×
    3
    = 3√3 : √2
    2

    Correct Option: B

    Volume of cylinder
    =
    πr1²h1
    Volume of cone
    1
    πr2²h2
    3

    = 3.
    r1
    ²
    h1
    r2h2

    = 3 ×
    3
    ² ×
    2
    23

    = 3 ×
    3
    = 3√3 : √2
    2



  1. The curved surface area and the total surface area of a cylinder are in the ratio 1 : 2. If the total surface area of the right cylinder is 616 cm², then its volume is :









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    2πrh : 2πrh + 2πr&up2;= 1 : 2
    ⇒ 2πrh : 616 = 1 : 2

    ⇒ 2πrh =
    616
    = 308
    2

    ∴ 2πrh + 2πr² = 616
    → 308 + 2πr² = 616
    ⇒ 2πr² = 308
    ⇒ r² =
    308 × 7
    = 49
    22 × 2

    ⇒ r = 7
    ∴ 2 ×
    22
    × 7 × h = 308
    2

    ⇒ h =
    308
    = 7
    44

    ∴ Volume of cylinder = πr²h

    Correct Option: D

    2πrh : 2πrh + 2πr&up2;= 1 : 2
    ⇒ 2πrh : 616 = 1 : 2

    ⇒ 2πrh =
    616
    = 308
    2

    ∴ 2πrh + 2πr² = 616
    → 308 + 2πr² = 616
    ⇒ 2πr² = 308
    ⇒ r² =
    308 × 7
    = 49
    22 × 2

    ⇒ r = 7
    ∴ 2 ×
    22
    × 7 × h = 308
    2

    ⇒ h =
    308
    = 7
    44

    ∴ Volume of cylinder = πr²h


  1. The perimeter of the base of a right circular cylinder is ‘a’ unit. If the volume of the cylinder is V cubic unit, then the height of the cylinder is









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    If the radius of base of cylinder be r units and its height be h units, then
    2πr = a

    ⇒ r =
    a
    units

    ∴ Volume of cylinder = πr²h
    ⇒ V = π ×
    × h
    4π²

    ⇒ h =
    4π V
    units

    Correct Option: D

    If the radius of base of cylinder be r units and its height be h units, then
    2πr = a

    ⇒ r =
    a
    units

    ∴ Volume of cylinder = πr²h
    ⇒ V = π ×
    × h
    4π²

    ⇒ h =
    4π V
    units



  1. What is the height of a cylinder that has the same volume and radius as a sphere of diameter 12 cm ?









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    Volume of sphere =
    4
    π × (6)³ cu.cm.
    3

    ∴ Volume of cylinder = πr²h = π × (6)² × h
    Now, π × (6)² × h =
    4
    π × (6)³ cu.cm.
    3

    ⇒ π =
    4
    × 6 = 8 cm.
    3

    Correct Option: D

    Volume of sphere =
    4
    π × (6)³ cu.cm.
    3

    ∴ Volume of cylinder = πr²h = π × (6)² × h
    Now, π × (6)² × h =
    4
    π × (6)³ cu.cm.
    3

    ⇒ π =
    4
    × 6 = 8 cm.
    3