Mensuration


  1. From each of the four corners of a rectangular sheet of dimensions 25 cm × 20 cm, a square of side 2 cm is cut off and a box is made. The volume of the box is









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    Length of box = 25 – 2 × 2 = 21 cm.
    Width of box = 20 – 2 × 2 = 16 cm.
    Height of box = 2 cm.
    ∴ Volume of box = (21 × 16 × 2) cu. cm. = 672 cu. cm.

    Correct Option: B


    Length of box = 25 – 2 × 2 = 21 cm.
    Width of box = 20 – 2 × 2 = 16 cm.
    Height of box = 2 cm.
    ∴ Volume of box = (21 × 16 × 2) cu. cm. = 672 cu. cm.


  1. A solid sphere of radius 3 cm is melted to form a hollow right circular cylindrical tube of length 4 cm and external radius 5 cm. The thickness of the tube is









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    Volume of solid sphere =
    4
    π(3)³
    3

    = 36π cu. cm.
    Volume of the metal of tube = π(R² – r²)h cu. cm.
    where R = 5 cm. r = in-radius
    ∴ π(R² – r²) h = 36π
    ⇒ (25 – r²) × 4 = 36
    ⇒ 25 – r² =
    36
    = 9
    4

    ⇒ r² = 25 – 9 = 16
    ⇒ r = 16 = 4 cm.
    7there4; Thickness of tube = 5 – 4 = 1 cm.

    Correct Option: A

    Volume of solid sphere =
    4
    π(3)³
    3

    = 36π cu. cm.
    Volume of the metal of tube = π(R² – r²)h cu. cm.
    where R = 5 cm. r = in-radius
    ∴ π(R² – r²) h = 36π
    ⇒ (25 – r²) × 4 = 36
    ⇒ 25 – r² =
    36
    = 9
    4

    ⇒ r² = 25 – 9 = 16
    ⇒ r = 16 = 4 cm.
    7there4; Thickness of tube = 5 – 4 = 1 cm.



  1. Three small lead spheres of radii 3 cm, 4 cm and 5 cm respectively, are melted into a single sphere. The diameter of the new sphere is









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    Volume of new single sphere =
    4
    π (r1³ + r2³ + r3³)
    3

    =
    4
    π (3³ + 4³ + 5³) cu.cm.
    3

    =
    4
    π (27 + 64 + 125) cu.cm.
    3

    =
    4
    π × 216 cu.cm.
    3

    4
    πR³ =
    4
    π × 216
    33

    where R = radius of new sphere
    ∴ R³ = 216
    ⇒ R = ³√216 = ³√6 × 6 × 6 = 6 cm
    ∴ Diameter of new sphere = 2 × 6 = 12

    Correct Option: D

    Volume of new single sphere =
    4
    π (r1³ + r2³ + r3³)
    3

    =
    4
    π (3³ + 4³ + 5³) cu.cm.
    3

    =
    4
    π (27 + 64 + 125) cu.cm.
    3

    =
    4
    π × 216 cu.cm.
    3

    4
    πR³ =
    4
    π × 216
    33

    where R = radius of new sphere
    ∴ R³ = 216
    ⇒ R = ³√216 = ³√6 × 6 × 6 = 6 cm
    ∴ Diameter of new sphere = 2 × 6 = 12


  1. On a rainy day, 60 cm of rain is recorded in a region. What is the volume of water collected in an open and empty rectangular water tank that measures 12 m (length) ×10 m (width) and 50 cm (depth)?









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    Water stored in tank =
    12 × 10 × 15
    = 60 cu. metre
    100

    = Capacity of tank.

    Correct Option: C

    Water stored in tank =
    12 × 10 × 15
    = 60 cu. metre
    100

    = Capacity of tank.



  1. A hemispherical bowl of internal radius 9 cm, contains a liquid. This liquid is to be filled into small cylindrical bottles of diameter 3 cm and height 4 cm. Then the number of bottles necessary to empty the bowl is









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    Volume of bowl =
    2
    πr³
    3

    =
    2
    π × 9 × 9 × 9
    3

    = 486p cu. cm.
    = volume of liquid Volume of 1 bottle = πR³H
    = π ×
    3
    ×
    3
    × 4
    22

    ∴ Number of bottles =
    486π
    = 54

    Correct Option: D

    Volume of bowl =
    2
    πr³
    3

    =
    2
    π × 9 × 9 × 9
    3

    = 486p cu. cm.
    = volume of liquid Volume of 1 bottle = πR³H
    = π ×
    3
    ×
    3
    × 4
    22

    ∴ Number of bottles =
    486π
    = 54