Mensuration
- Two adjacent sides of a parallelogram are of length 15 cm and 18 cm. If the distance between two smaller sides is 12 cm, then the distance between two bigger sides is
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Area of the parallelogram = Base × Height
= 15 × 12 = 180 sq.cm.
∴ 180 = 18 × height
⇒ Height = 10 cmCorrect Option: B
Area of the parallelogram = Base × Height
= 15 × 12 = 180 sq.cm.
∴ 180 = 18 × height
⇒ Height = 10 cm
- A parallelogram ABCD has sides AB = 24 cm and AD = 16 cm. The distance between the sides AB and DC is 10 cm. Find the distance between the sides AD and BC.
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Area of the parallelogram = Base × Height
= 24 × 10 = 240 sq.cm.
If the required distance be x cm, then
240 = 16 × x⇒ x = 240 = 15 cm 16 Correct Option: C
Area of the parallelogram = Base × Height
= 24 × 10 = 240 sq.cm.
If the required distance be x cm, then
240 = 16 × x⇒ x = 240 = 15 cm 16
- The adjacent sides of a parallelogram are 36 cm and 27 cm in length. If the distance between the shorter sides is 12 cm, then the distance between the longer sides is
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Area of parallelogram = base × height
= 27 × 12 = 324 sq. cm.
Again,
324 = 36 × h⇒ h = 324 = 9 cm 36 Correct Option: D
Area of parallelogram = base × height
= 27 × 12 = 324 sq. cm.
Again,
324 = 36 × h⇒ h = 324 = 9 cm 36
- If the diagonals of a rhombus are 8 and 6, then the square of its size is
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BO = 4 units; OC = 3 units
∠BOC = 90°
∴ BC = √4² + 3² = 5 units
∴ BC² = 25 sq. unitsCorrect Option: A
BO = 4 units; OC = 3 units
∠BOC = 90°
∴ BC = √4² + 3² = 5 units
∴ BC² = 25 sq. units
- One of the four angles of a rhombus is 60°. If the length of each side of the rhombus is 8 cm, then the length of the longer diagonal is
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∠BAD = 60°
∴ ∠BAO = 30° ∠ABO = 60°∴ sin 60° = OA AB ⇒ √3 × 8 = OA 2
⇒ OA = 4√3
∴ AC = 8√3 cmCorrect Option: A
∠BAD = 60°
∴ ∠BAO = 30° ∠ABO = 60°∴ sin 60° = OA AB ⇒ √3 × 8 = OA 2
⇒ OA = 4√3
∴ AC = 8√3 cm