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Aptitude miscellaneous
  1. The diagonals of a rhombus are 24 cm and 10 cm. The perimeter of the rhombus (in cm) is :








  1. View Hint View Answer Discuss in Forum

    Using Rule 12,
    If d1 and d2 are the lengths of diagonals of a rhombus. Then
    Perimeter = 2√d1² + d2² = √24² + 10²
    = √276 + 100 = 2√676
    = 2 × 26 = 52 cm

    Correct Option: D

    Using Rule 12,
    If d1 and d2 are the lengths of diagonals of a rhombus. Then
    Perimeter = 2√d1² + d2² = √24² + 10²
    = √276 + 100 = 2√676
    = 2 × 26 = 52 cm

  1. The perimeter of a rhombus is 40 cm. If one of the diagonals be 12cm long, what is the length of the other diagonal ?








  1. View Hint View Answer Discuss in Forum

    Using Rule 12, 4 × side = 40 cm [given]

    ⇒ Side =
    40
    		= 10 cm.
    4


    In ∆AOB,
    OB = √(10)² - (6)²
    = √100 - 36 = √64 = 8 cm
    ∴ Diagonal BD = 8 × 2 = 16 cm

    Correct Option: C

    Using Rule 12, 4 × side = 40 cm [given]

    ⇒ Side =
    40
    		= 10 cm.
    4


    In ∆AOB,
    OB = √(10)² - (6)²
    = √100 - 36 = √64 = 8 cm
    ∴ Diagonal BD = 8 × 2 = 16 cm

  1. The perimeter of a rhombus is 40 cm. If the length of one of its diagonals be 12 cm, the length of the other diagonal is








  1. View Hint View Answer Discuss in Forum

    Using Rule 12,
    If d1 and d2 be the diagonals of a rhombus, we have
    Perimeter = 4 × side
    = 2√d1² + d2²

    ∵ side =
    1
    		√d1² + d2²
    2

    ⇒ 40 = 2√12² + d2²
    ⇒ 20 = √144 + d2²
    ⇒ 144 + d2² = 20² = 400
    ⇒ d2² = 400 – 144 = 256
    ⇒ d2 = √256
    = 16 cm.

    Correct Option: C

    Using Rule 12,
    If d1 and d2 be the diagonals of a rhombus, we have
    Perimeter = 4 × side
    = 2√d1² + d2²

    ∵ side =
    1
    		√d1² + d2²
    2

    ⇒ 40 = 2√12² + d2²
    ⇒ 20 = √144 + d2²
    ⇒ 144 + d2² = 20² = 400
    ⇒ d2² = 400 – 144 = 256
    ⇒ d2 = √256
    = 16 cm.

  1. The area of a circle is 38.5 sq. cm. Its circumference (in cm) is (use π = 22/7) :








  1. View Hint View Answer Discuss in Forum

    Using Rule 14, We know that Area of circle = πr²
    According to question, πr² = 38.5

    ⇒ r² =
    38.5
    		 × 7 = (3.5)²
    22

    ⇒ r = 3.5 cm
    ∴ Circumference of circle = 2πr = 2 ×
    22
    		 × 3.5 = 22 cm
    7

    Correct Option: A

    Using Rule 14, We know that Area of circle = πr²
    According to question, πr² = 38.5

    ⇒ r² =
    38.5
    		 × 7 = (3.5)²
    22

    ⇒ r = 3.5 cm
    ∴ Circumference of circle = 2πr = 2 ×
    22
    		 × 3.5 = 22 cm
    7

  1. The diameter of a toy wheel is 14 cm. What is the distance travelled by it in 15 revolutions?








  1. View Hint View Answer Discuss in Forum

    Using Rule 7,

    Circumference of wheel = πD

    =
    22
    		 × 14 = 44 cm
    7

    ∴ Total distance travelled by wheel in 15 revolutions = 15 × 44 cm = 660 cm

    Correct Option: B

    Using Rule 7,

    Circumference of wheel = πD

    =
    22
    		 × 14 = 44 cm
    7

    ∴ Total distance travelled by wheel in 15 revolutions = 15 × 44 cm = 660 cm