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The perimeter of a rhombus is 40 cm. If one of the diagonals be 12cm long, what is the length of the other diagonal ?
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- 12 cm
- 136 cm
- 16 cm
- 44 cm
- 12 cm
Correct Option: C
Using Rule 12, 4 × side = 40 cm [given]
| ⇒ Side = | = 10 cm. | |
| 4 |
In ∆AOB,
OB = √(10)² - (6)²
= √100 - 36 = √64 = 8 cm
∴ Diagonal BD = 8 × 2 = 16 cm
